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胰凝乳蛋白酶原的芳香族质子磁共振谱的表征

Characterization of the aromatic proton magnetic resonance spectrum of crambin.

作者信息

Lecomte J T, Llinás M

出版信息

Biochemistry. 1984 Sep 25;23(20):4799-807. doi: 10.1021/bi00315a041.

DOI:10.1021/bi00315a041
PMID:6548643
Abstract

The hydrophobic protein crambin (Mr 4715) has an aromatic content of one phenylalanyl residue (site 13) and two tyrosyl residues (sites 29 and 44). The aromatic residues have been studied by 1H NMR spectroscopy at 300 and 600 MHz for crambin dissolved in deuterated glacial acetic acid and in aqueous organic media. In particular, a 3:1 acetone/water mixture affords a solvent system of low viscosity, which yields very narrow line protein spectra. The aromatic proton spectrum is unusual in that signals are doubled. Spectral simulation of modified and unmodified crambin aromatic spin systems can be accomplished only by assuming that the protein is a mixture of two species. Dynamic 1H-[1H] Overhauser experiments centered on the aromatic doublets of Tyr29 indicate that the two species do not interconvert within 2 s. NMR spectra of crambin samples obtained by repeated crystallization in 17:3 acetone/water indicate that the process enriches the mixture with one component that does not convert to the other, even upon heating of the sample to 351 K. The combined evidence strongly favors the view that the doubled spectrum results from a compositional heterogeneity, most likely a mixture of two homologues, rather than from an equilibrium between interconvertible forms. This is important in view of the fact that its crystallographic structure, solved to 1.5-A resolution [Hendrickson, W.A., & Teeter, M. M. (1981) Nature (London) 290, 107-113], is based on samples containing the two species.(ABSTRACT TRUNCATED AT 250 WORDS)

摘要

疏水蛋白克拉宾(分子量4715)含有一个苯丙氨酰残基(第13位)和两个酪氨酰残基(第29位和第44位),具有芳香族成分。对于溶解在氘代冰醋酸和水性有机介质中的克拉宾,已通过300和600兆赫的1H核磁共振光谱对芳香族残基进行了研究。特别地,3:1的丙酮/水混合物提供了一种低粘度的溶剂体系,可产生非常窄线宽的蛋白质光谱。芳香族质子光谱不同寻常之处在于信号是双重的。只有假设该蛋白质是两种物质的混合物,才能完成对修饰和未修饰的克拉宾芳香族自旋体系的光谱模拟。以Tyr29的芳香族双峰为中心的动态1H-[1H]奥弗豪泽实验表明,这两种物质在2秒内不会相互转化。通过在17:3的丙酮/水体系中反复结晶获得的克拉宾样品的核磁共振光谱表明,即使将样品加热到351K,该过程也会使混合物中富含一种不会转化为另一种的成分。综合证据强烈支持这样一种观点,即双重光谱是由成分异质性导致的,很可能是两种同系物的混合物,而不是由可相互转化形式之间的平衡导致的。鉴于其晶体结构(分辨率为1.5埃[亨德里克森,W.A.,& 蒂特,M.M.(1981年)《自然》(伦敦)290,107 - 113])是基于含有这两种物质的样品,这一点很重要。(摘要截取自250字)

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