Paul R J
J Gen Physiol. 1983 Mar;81(3):337-54. doi: 10.1085/jgp.81.3.337.
Frog sartorius muscle stimulated isometrically for 3 s every 256 s to attain a steady state in which initial heat (QI), recovery heat (QR), rate of O2 consumption (JO2), and isometric force (PO) generated are constant for each cycle. For a 3-s tetanus given every 256 s, JO2 was 0.106 mumol/(min . g blotted weight), approximately 71% of the maximum rate observed, whereas lactate production was negligible under these conditions. QI, QT(= QI + QR), and QT/QI were 88.2, 181.5, 2.06 mJ/g blotted weight, respectively. The high-energy phosphate breakdown (delta approximately P) breakdown during the first 3-s tetanus was not different from that during a contraction in the steady state and averaged 1.1 mumol/g blotted weight. Less than half of the initial heat could be accounted for in terms of the extent of the known chemical reactions occurring during contraction. From the stoichiometry of the theoretical biochemical pathways, the amount of ATP synthesized in the steady state exceeds delta approximately P during contraction by more than twofold, corresponding to an apparent ADP:O ratio of 1.5. If it is assumed that carbohydrate oxidation is the only net chemical reaction in the steady state, the total heat production can be explained on the basis of the measured JO2. Under this assumption, heat production during recovery was less than that expected on the basis of the oxygen consumption and delta approximately P during contraction. These observations support the hypothesis that the unexplained enthalpy production and low apparent ADP:O ratio are causally related, i.e., that the reaction(s) producing the unexplained heat during contraction is reversed during the recovery period.
每隔256秒对青蛙缝匠肌进行3秒的等长刺激,以达到一种稳定状态,在此状态下,每个周期产生的初始热(QI)、恢复热(QR)、耗氧率(JO2)和等长力(PO)都是恒定的。对于每隔256秒进行一次的3秒强直收缩,JO2为0.106微摩尔/(分钟·克湿重),约为观察到的最大速率的71%,而在这些条件下乳酸生成可忽略不计。QI、QT(= QI + QR)和QT/QI分别为88.2、181.5、2.06毫焦/克湿重。第一个3秒强直收缩期间的高能磷酸键分解(δ≈P)与稳定状态下收缩期间的分解没有差异,平均为1.1微摩尔/克湿重。根据收缩期间发生的已知化学反应程度,初始热的不到一半可以得到解释。从理论生化途径的化学计量关系来看,稳定状态下合成的ATP量超过收缩期间的δ≈P两倍多,对应于表观ADP:O比为1.5。如果假设碳水化合物氧化是稳定状态下唯一的净化学反应,那么总产热可以根据测得的JO2来解释。在此假设下,恢复期间的产热低于根据收缩期间的耗氧量和δ≈P预期的值。这些观察结果支持这样的假设,即无法解释的焓产生和低表观ADP:O比存在因果关系,也就是说,收缩期间产生无法解释热量的反应在恢复期间会逆转。