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培养的小鼠细胞中氨甲蝶呤耐药性的快速出现。

Rapid emergence of methotrexate resistance in cultured mouse cells.

作者信息

Rath H, Tlsty T, Schimke R T

出版信息

Cancer Res. 1984 Aug;44(8):3303-6.

PMID:6744265
Abstract

We have examined the time required for mouse 3T6 cells to become resistant to 200 nM methotrexate by three selection protocols: (a) a single-step 0 to 200 nM dose; (b) a two-step 0 to 80 to 200 nM dose; and (c) a multistep 0 to 40 to 80 to 120 to 160 to 200 nM dose. An initial inoculum of 5 X 10(5) cells was grown to 10(6) cells at each increment of methotrexate, reduced to 5 X 10(5) cells, and again grown to 10(6) cells at the next increment. The total elapsed time required for an initial inoculum of 5 X 10(5) cells to grow to 1 X 10(6) cells resistant to 200 nM methotrexate was 45, 21, and 6.5 days, respectively, for the three drug dosage schedules. The single-step resistant variants did not contain amplified dihydrofolate reductase genes, whereas cells resistant to 200 nM methotrexate by the two stepwise selections were resistant as a result of a 6-fold amplification of the dihydrofolate reductase gene. We conclude that the resistance to 200 nM methotrexate resulting from gene amplification did not preexist in the initial population but was generated during the selection process. These results are discussed in terms of the emergence of drug resistance during the course of chemotherapy of tumors.

摘要

我们通过三种选择方案研究了小鼠3T6细胞对200 nM甲氨蝶呤产生抗性所需的时间:(a) 单步0至200 nM剂量;(b) 两步0至80至200 nM剂量;以及(c) 多步0至40至80至120至160至200 nM剂量。在每次增加甲氨蝶呤时,将5×10⁵个细胞的初始接种物培养至10⁶个细胞,然后减少至5×10⁵个细胞,并在下次增加时再次培养至10⁶个细胞。对于三种药物剂量方案,5×10⁵个细胞的初始接种物生长至对200 nM甲氨蝶呤产生抗性的1×10⁶个细胞所需的总时间分别为45天、21天和6.5天。单步抗性变体不包含扩增的二氢叶酸还原酶基因,而通过两步选择对200 nM甲氨蝶呤产生抗性的细胞是由于二氢叶酸还原酶基因6倍扩增而产生抗性的。我们得出结论,由基因扩增导致的对200 nM甲氨蝶呤的抗性在初始群体中并不预先存在,而是在选择过程中产生的。根据肿瘤化疗过程中耐药性的出现对这些结果进行了讨论。

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