Abeles R H, Fish S, Lapinskas B
Biochemistry. 1982 Oct 26;21(22):5557-62. doi: 10.1021/bi00265a027.
S-Adenosylhomocysteinase (SAHase), a tetrameric enzyme, is inactivated by 2'-deoxyadenosine (2'dAdo) in a time-dependent process [Hirshfield, M. S. (1979) J. Biol. Chem. 254, 22-25]. It has been proposed that inactivation involves oxidation of 2'dAdo at C-3' by enzyme-bound nicotinamide adenine dinucleotide (NAD), subsequent proton abstraction at C-2', and elimination of adenine. This results in irreversible formation of enzyme-bound NADH and of adenine (Ade) and inactivation [Abeles, R. H., TAshjian, A. H., Jr., & Fish, S (1980) Biochem. Biophys. Res. Commun. 95, 612-617]. It has now been established that upon inactivation of SAHase with deoxy[2'(R)-3H]adenosine, 3H2O is formed. This is consistent with the proposed mechanism and of 3H2O release shows that maximally two of the four subunits participate in the reaction that results in 3H2O release. Reaction of SAHase with 2'dAdo results in reduction of two of the enzyme-bound NAD molecules. However, all four NAD molecules can be reduced by NaBH4, but only two are reduced to C-4 NADH. When the enzyme is inactivated with adenine-labeled 2'dAdo, radioactivity corresponding to 0.5-1.0 mumol of 2'dAdo binds tightly per micromole of subunit. This radioactive material is not removed from the enzyme by extensive dialysis but can be displaced by unlabeled 2'dAdo or Ade. After denaturation of the complex, radioactive material is released. Of this material 80-90% is adenine and less than 1% 2'dAdo. 2'dAdo also binds tightly to the enzyme reduced with NaBH4. Upon denaturation mostly adenine (80-90%) is released. Reaction of [2'-3H]2'dAdo with enzyme reduced with NaBH4 does not result in 3H2O formation. We conclude that the enzyme catalyzes the release of adenine from 2'dAdo by two mechanisms: One involves formation of 3'keto-2'dAdo and subsequent elimination of adenine. The other does not involve oxidation of 2'dAdo and probably is a hydrolytic process. It is proposed that the ability of the enzyme to carry out the hydrolytic process is a direct consequence of the manner in which 2'dAdo as well as the normal substrate binds to the enzyme, i.e., hydrogen-bond interaction of the protein with the adenine moiety and distortion of the ribose ring. When adenine-labeled adenosine is added to the enzyme, radioactivity corresponding to 0.5 mumol/mumol of subunit is associated with the protein after gel filtration. Of the radioactive material bound to the protein, 20% is adenine, 15% is adenosine, and the remaining radioactivity is present in unidentified compounds. The adenine bound to the enzyme does not participate in the catalytic process, and we conclude that it is bound to two of the subunits that do not participate in catalysis. Possible, these two subunits have a regulatory function. SAHase probably consists of two nonequivalent pairs of subunits. Only one pair participates in catalysis, but all four subunits probably bind Ado and 2'dAdo. We have confirmed the fact that the carbocyclic analogue of adenosine inactivates SAHase [Guranowski, A., Montgomery, J. A., 110-115]...
S-腺苷同型半胱氨酸酶(SAHase)是一种四聚体酶,在一个时间依赖性过程中被2'-脱氧腺苷(2'dAdo)失活[赫希菲尔德,M. S.(1979年)《生物化学杂志》254卷,22 - 25页]。有人提出失活过程涉及酶结合的烟酰胺腺嘌呤二核苷酸(NAD)将2'dAdo的C - 3'氧化,随后C - 2'上的质子被夺取,以及腺嘌呤的消除。这导致酶结合的NADH、腺嘌呤(Ade)的不可逆形成以及失活[阿贝莱斯,R. H.,塔什吉安,A. H.,小,&菲什,S(1980年)《生物化学与生物物理研究通讯》95卷,612 - 617页]。现已确定,用脱氧[2'(R)-3H]腺苷使SAHase失活时,会形成3H2O。这与提出的机制一致,并且3H2O的释放表明四个亚基中最多有两个参与导致3H2O释放的反应。SAHase与2'dAdo反应会使两个酶结合的NAD分子还原。然而,所有四个NAD分子都能被NaBH4还原,但只有两个被还原为C - 4 NADH。当用腺嘌呤标记的2'dAdo使酶失活时,每微摩尔亚基紧密结合相当于0.5 - 1.0微摩尔2'dAdo的放射性物质。这种放射性物质不能通过广泛透析从酶中去除,但可以被未标记的2'dAdo或Ade取代。复合物变性后,放射性物质释放出来。这种物质中80 - 90%是腺嘌呤,2'dAdo不到1%。2'dAdo也紧密结合到用NaBH4还原的酶上。变性后大部分腺嘌呤(80 - 90%)被释放出来。[2'-3H]2'dAdo与用NaBH4还原的酶反应不会导致3H2O形成。我们得出结论,该酶通过两种机制催化从2'dAdo释放腺嘌呤:一种涉及形成3'-酮基-2'dAdo并随后消除腺嘌呤。另一种不涉及2'dAdo的氧化,可能是一个水解过程。有人提出酶进行水解过程的能力是2'dAdo以及正常底物与酶结合方式的直接结果,即蛋白质与腺嘌呤部分的氢键相互作用以及核糖环的扭曲。当将腺嘌呤标记的腺苷加入到酶中时,凝胶过滤后每微摩尔亚基相当于0.5微摩尔的放射性物质与蛋白质结合。与蛋白质结合的放射性物质中,20%是腺嘌呤,15%是腺苷,其余放射性存在于未鉴定的化合物中。与酶结合的腺嘌呤不参与催化过程,我们得出结论它与不参与催化的两个亚基结合。可能,这两个亚基具有调节功能。SAHase可能由两对不等价的亚基组成。只有一对参与催化,但所有四个亚基可能都结合Ado和2'dAdo。我们已经证实了腺苷碳环类似物使SAHase失活这一事实[古兰诺夫斯基,A.,蒙哥马利,J. A.,110 - 115]...