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3α,7α,12α,24ξ-四羟基-5β-胆甾烷-26-酸的改进合成方法。

Improved synthesis of 3 alpha, 7 alpha, 12 alpha, 24 = xi-tetrahydroxy-5 beta-cholestan-26-oic acid.

作者信息

Batta A K, Tint G S, Dayal B, Shefer S, Salen G

出版信息

Steroids. 1982 Jun;39(6):693-702. doi: 10.1016/0039-128x(82)90140-4.

Abstract

This paper describes three simple and short methods for the conversion of cholic acid into cholylaldehyde with protected hydroxyl groups. The first method involves lithium aluminum hydride reduction of the tetrahydropyranyl ether of methyl cholate and oxidation of the resulting primary alcohol with pyridinium chlorochromate. The second method employs diborane for the reduction of the -COOH group to the -CH2OH group, while the third method involves the reduction of 3 alpha, 7 alpha, 12 alpha-triformyloxy-5 beta-cholan-24-oic acid (as the acid chloride) directly into 3 alpha, 7 alpha, 12 alpha-triformyloxy-5 beta-cholan-24-al with TMA-ferride (tetramethylammonium hydridoirontetracarbonyl). The aldehyde obtained by any of the above methods underwent smooth Reformatsky reaction with ethyl alpha-bromopropionate to yield 3 alpha, 7 alpha, 12 alpha, 24 xi-tetrahydroxy-5 beta-cholestan-26-oic acid.

摘要

本文描述了三种将胆酸转化为具有保护羟基的胆醛的简单且简短的方法。第一种方法涉及用氢化铝锂还原胆酸甲酯的四氢吡喃醚,并使用氯铬酸吡啶鎓将所得的伯醇氧化。第二种方法使用乙硼烷将 -COOH 基团还原为 -CH2OH 基团,而第三种方法涉及用 TMA-亚铁(四羰基氢铱酸四甲基铵)将 3α,7α,12α-三羟基甲酰氧基-5β-胆烷-24-酸(作为酰氯)直接还原为 3α,7α,12α-三羟基甲酰氧基-5β-胆烷-24-醛。通过上述任何一种方法得到的醛与α-溴丙酸乙酯顺利进行Reformatsky反应,生成3α,7α,12α,24ξ-四羟基-5β-胆甾烷-26-酸。

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