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通过闪光光解研究黄素发色团的双电子和单电子还原模式的区别。

Distinction of 2e- and 1e- reduction modes of the flavin chromophore as studied by flash photolysis.

作者信息

Hemmerich P, Knappe W R, Kramer H E, Traber R

出版信息

Eur J Biochem. 1980 Mar;104(2):511-20. doi: 10.1111/j.1432-1033.1980.tb04453.x.

DOI:10.1111/j.1432-1033.1980.tb04453.x
PMID:7363903
Abstract

Evidence is given for the fact that the excited flavin triplet (3Flox) exhibits competitive 1e- and 2e- transfer chemistry, depending on the nature of the photosubstrate. As an 'external' photo-reductant, the 2e- donor borohydride has been investigated. Borohydride is found to compete effectively with the 'internal' 1e- donors, namely excess starting flavin in the ground state (Flox) and, as primary product, (alkyl)dihydroflavin (RFlredH). It will be shown that some of the flavin radicals, observed by earlier authors in the reaction of 3Flox with CH or C-COO- substrates or in the autophotolytic side-chain cleavage of riboflavin, are due to the dye-dye reaction (I): 3Flox + Flox H+ leads to HFl + Fl+ -H+ leads to 2Flox. (I) In contrast flavin photoreduction by borohydride or hydrocarbon substrates need not involve radicals, but may in fact be a hydride or 'carbanion-plus-proton' addition towards the highly polar and considerably basic (pK = 4.4) acceptor triplet (cf. reaction II) (see text: Formula). The products are much more photoreactive than the starting substrates, which leads to the secondary photocomproportionation (III): 3Flox + R-FlredH leads to HFl + RFl, (R = alkyl or H). (III) This latter reaction is the second source of radicals in the system. This (cf. II) 'photohydrogenation' of flavin is mechanistically related to the biological reduction of flavin by CH substrates.

摘要

有证据表明,激发态黄素三线态(3Flox)根据光底物的性质表现出竞争性的单电子和双电子转移化学过程。作为一种“外部”光还原剂,对双电子供体硼氢化物进行了研究。发现硼氢化物能有效地与“内部”单电子供体竞争,即基态下过量的起始黄素(Flox)以及作为主要产物的(烷基)二氢黄素(RFlredH)。结果表明,早期作者在3Flox与CH或C-COO-底物反应或核黄素的自光解侧链裂解反应中观察到的一些黄素自由基是由于染料-染料反应(I):3Flox + Flox H+ 生成HFl + Fl+ -H+ 进而生成2Flox。(I)相比之下,硼氢化物或烃类底物对黄素的光还原不需要涉及自由基,实际上可能是向高极性且碱性较强(pK = 4.4)的受体三线态进行氢化物或“碳负离子加质子”的加成反应(参见反应II)(见正文:化学式)。产物比起始底物的光反应性更强,这导致了二级光归中反应(III):3Flox + R-FlredH 生成HFl + RFl,(R = 烷基或H)。(III)后一个反应是体系中自由基的第二个来源。黄素的这种(参见II)“光氢化”在机理上与黄素被CH底物进行的生物还原有关。

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