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乳酸乳球菌中的基因失活:组氨酸生物合成

Gene inactivation in Lactococcus lactis: histidine biosynthesis.

作者信息

Delorme C, Godon J J, Ehrlich S D, Renault P

机构信息

Laboratoire de Génétique Microbienne, Institut National de la Recherche Agronomique, Jouy en Josas, France.

出版信息

J Bacteriol. 1993 Jul;175(14):4391-9. doi: 10.1128/jb.175.14.4391-4399.1993.

Abstract

Lactococcus lactis strains from dairy and nondairy sources were tested for the ability to grow in the absence of histidine. Among 60 dairy strains tested, 56 required histidine, whereas only 1 of 11 nondairy strains had this requirement. Moreover, 10 of the 56 auxotrophic strains were able to grow in the presence of histidinol (Hol+), the immediate histidine precursor. This indicates that adaptation to milk often results in histidine auxotrophy. The histidine operon was detected by Southern hybridization in eight dairy auxotrophic strains tested. A large part of the histidine operon (8 kb, containing seven histidine biosynthetic genes and three unrelated open reading frames [ORFs]) was cloned from an auxotroph, which had an inactive hisD gene, as judged by its inability to grow on histidinol. Complementation analysis of three genes, hisA, hisB, and hisG, in Escherichia coli showed that they also were inactive. Sequence analysis of the cloned histidine region, which revealed 98.6% overall homology with that of the previously analyzed prototrophic strain, showed the presence of frameshift mutations in three his genes, hisC, hisG, and hisH, and two genes unrelated to histidine biosynthesis, ORF3 and ORF6. In addition, several mutations were detected in the promoter region of the operon. Northern (RNA) hybridization analysis showed a much lower amount of the his transcript in the auxotrophic strain than in the prototrophic strain. The mutations detected account for the histidine auxotrophy of the analyzed strain. Certain other dairy auxotrophic strains carry a lower number of mutations, since they were able to revert either to a Hol+ phenotype or to histidine prototrophy.

摘要

对来自乳制品和非乳制品来源的乳酸乳球菌菌株进行了在无组氨酸条件下生长能力的测试。在测试的60株乳制品菌株中,56株需要组氨酸,而11株非乳制品菌株中只有1株有此需求。此外,56株营养缺陷型菌株中有10株能够在组氨酸醇(Hol+)(组氨酸的直接前体)存在的情况下生长。这表明对牛奶的适应通常会导致组氨酸营养缺陷。通过Southern杂交在测试的8株乳制品营养缺陷型菌株中检测到了组氨酸操纵子。从一株营养缺陷型菌株中克隆了组氨酸操纵子的很大一部分(8 kb,包含7个组氨酸生物合成基因和3个不相关的开放阅读框[ORF]),根据其在组氨酸醇上不能生长判断,该菌株的hisD基因无活性。在大肠杆菌中对hisA、hisB和hisG三个基因的互补分析表明它们也无活性。对克隆的组氨酸区域的序列分析显示,其与先前分析的原养型菌株的序列总体同源性为98.6%,结果表明在三个his基因hisC、hisG和hisH以及两个与组氨酸生物合成无关的基因ORF3和ORF6中存在移码突变。此外,在操纵子的启动子区域检测到了几个突变。Northern(RNA)杂交分析表明,营养缺陷型菌株中his转录本的量比原养型菌株低得多。检测到的突变解释了所分析菌株的组氨酸营养缺陷。某些其他乳制品营养缺陷型菌株携带的突变数量较少,因为它们能够回复到Hol+表型或组氨酸原养型。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/4463/204879/83c5e97bb494/jbacter00056-0144-a.jpg

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