Suppr超能文献

细胞色素P450BM-3黄素蛋白结构域还原机制的平衡态和瞬态分光光度研究

Equilibrium and transient state spectrophotometric studies of the mechanism of reduction of the flavoprotein domain of P450BM-3.

作者信息

Sevrioukova I, Shaffer C, Ballou D P, Peterson J A

机构信息

Department of Biochemistry, University of Texas Southwestern Medical Center at Dallas 75235-9038, USA.

出版信息

Biochemistry. 1996 Jun 4;35(22):7058-68. doi: 10.1021/bi960060a.

Abstract

The flavoprotein domain of P450BM-3 (BMR), which is functionally analogous to eukaryotic NADPH-P450 oxidoreductases, contains both FAD and FMN. When BMR is titrated with NADPH or sodium dithionite under anaerobic conditions, addition of 2 electron equivalents per mole of BMR results in the reduction of the high potential flavin (FMN) without the accumulation of semiquinone intermediates. Additional sodium dithionite first produces some neutral, blue flavin semiquinone radical and, finally, fully reduced FADH2. During reduction with NADPH, an absorbance increase characteristic of the formation of a flavin-pyridine nucleotide charge-transfer complex was observed only during the addition of the second mole of NADPH per mole of BMR. On the basis of these results, we conclude that the midpoint reduction potential for the FMN semiquinone/FMNH2 couple is more positive than that for FMN/FMN semiquinone. The kinetics of reduction of BMR with NADPH were studied by stopped-flow spectrophotometry. With a 1:1 ratio of NADPH to BMR, the absorbance changes can be fit to five consecutive first order reactions with rate constants of 350 s-1, 130 s-1, 27 s-1, 2.3 s-1, and 0.05 s-1. These reactions are most probably the following: (a) complex formation between BMR and NADPH; (b) reduction of FAD with formation of the NADP(+)-FADH- charge-transfer complex; (c) transfer of the first electron from FADH- to FMN to form an anionic, red FMN semiquinone leaving the FAD as the neutral, blue semiquinone. Precise identification of intermediates beyond this point is difficult. In the presence of a 10-fold molar excess of NADPH, the absorbance changes and rate constants are somewhat different due to the formation of several additional reduced species of BMR. The rate of the first step increases, confirming that this is the formation of the NADPH-BMR complex. Our results indicate that the kinetic and thermodynamic control of the flavins in BMR is significantly different from that in microsomal P450 reductase. The low potential of the anionic FMN semiquinone can be utilized to reduce the P450 heme. When the anionic semiquinone becomes protonated, its potential becomes more positive and it is readily reduced to FMNH2, which is not capable of reducing P450.

摘要

细胞色素P450BM-3(BMR)的黄素蛋白结构域在功能上类似于真核生物的NADPH-P450氧化还原酶,它同时含有黄素腺嘌呤二核苷酸(FAD)和黄素单核苷酸(FMN)。在厌氧条件下用NADPH或连二亚硫酸钠滴定BMR时,每摩尔BMR加入2个电子当量会导致高电位黄素(FMN)的还原,而不会积累半醌中间体。额外加入连二亚硫酸钠首先会产生一些中性的蓝色黄素半醌自由基,最终生成完全还原的FADH2。在用NADPH还原过程中,仅在每摩尔BMR加入第二摩尔NADPH时才观察到黄素 - 吡啶核苷酸电荷转移复合物形成所特有的吸光度增加。基于这些结果,我们得出结论,FMN半醌/FMNH2电对的中点还原电位比FMN/FMN半醌的中点还原电位更正。用停流分光光度法研究了用NADPH还原BMR的动力学。当NADPH与BMR的比例为1:1时,吸光度变化可以拟合为五个连续的一级反应,速率常数分别为350 s-1、130 s-1、27 s-1、2.3 s-1和0.05 s-1。这些反应很可能如下:(a)BMR与NADPH之间形成复合物;(b)FAD还原并形成NADP(+)-FADH-电荷转移复合物;(c)第一个电子从FADH-转移到FMN,形成阴离子型红色FMN半醌,而FAD则成为中性的蓝色半醌。在此之后精确鉴定中间体很困难。在存在10倍摩尔过量的NADPH时,由于形成了几种额外的BMR还原产物,吸光度变化和速率常数有所不同。第一步的速率增加,证实这是NADPH-BMR复合物的形成。我们的结果表明,BMR中黄素的动力学和热力学控制与微粒体P450还原酶中的显著不同。阴离子型FMN半醌的低电位可用于还原P450血红素。当阴离子半醌质子化时,其电位变得更正,并且很容易被还原为FMNH2,而FMNH2不能还原P450。

文献检索

告别复杂PubMed语法,用中文像聊天一样搜索,搜遍4000万医学文献。AI智能推荐,让科研检索更轻松。

立即免费搜索

文件翻译

保留排版,准确专业,支持PDF/Word/PPT等文件格式,支持 12+语言互译。

免费翻译文档

深度研究

AI帮你快速写综述,25分钟生成高质量综述,智能提取关键信息,辅助科研写作。

立即免费体验