牛白细胞介素-5编码cDNA的核苷酸序列。

The nucleotide sequence of the bovine interleukin-5-encoding cDNA.

作者信息

Mertens B, Gobright E, Seow H F

机构信息

International Livestock Research Institute (ILRI), Nairobi, Kenya.

出版信息

Gene. 1996 Oct 17;176(1-2):273-4. doi: 10.1016/0378-1119(96)00252-1.

DOI:10.1016/0378-1119(96)00252-1

PMID:8918267

Abstract

The nucleotide (nt) sequence encoding the bovine homologue of interleukin-5 (boIL-5) was determined. Total cDNA generated from stimulated bovine peripheral blood lymphocytes was used to amplify the boIL-5 gene using primers based on the 5' and 3' untranslated regions of the ovine IL-5 cDNA sequence. The boIL-5 coding sequence is 405 bp long, coding for a 15.2 kDa precursor protein of 134 amino acids (aa). Cleavage of a putative signal peptide of 19 aa yields a mature form of 13.1 kDa. Comparisons at the nt level revealed 96%, 81%, 74% and 73% identity with the ovine, human, mouse and rat IL-5 sequences, respectively, and 97%, 66%, 59% and 58% aa identity, respectively.

摘要

测定了编码牛白细胞介素-5（boIL-5）同源物的核苷酸（nt）序列。从受刺激的牛外周血淋巴细胞产生的总cDNA用于基于绵羊IL-5 cDNA序列的5'和3'非翻译区的引物扩增boIL-5基因。boIL-5编码序列长405 bp，编码一个由134个氨基酸（aa）组成的15.2 kDa前体蛋白。假定的19个aa的信号肽的切割产生13.1 kDa的成熟形式。在nt水平上的比较分别显示与绵羊、人、小鼠和大鼠IL-5序列的同一性为96%、81%、74%和73%，氨基酸同一性分别为97%、66%、59%和58%。