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虹鳟鱼肝细胞中二十二碳六烯酸的生物合成通过24碳中间体进行。

Biosynthesis of docosahexaenoic acid in trout hepatocytes proceeds via 24-carbon intermediates.

作者信息

Buzzi M, Henderson R J, Sargent J R

机构信息

NERC Unit of Aquatic Biochemistry, Department of Molecular and Biological Sciences, University of Stirling, Scotland, U.K.

出版信息

Comp Biochem Physiol B Biochem Mol Biol. 1997 Feb;116(2):263-7. doi: 10.1016/s0305-0491(96)00210-6.

Abstract

The role of 24:5n-3 and 24:6n-3 as intermediate in the formation of 22:6n-3 in trout liver was examined. Microsomes prepared from trout liver converted [1-14C]-eicosapentaenoic acid (20:5n-3) to 24: 5n-3 and 24:6n-3 but not docosahexaenoic acid (22:6n-3). The radiolabeled 24:5n-3 and 24:6n-3 were isolated from the microsomal incubations by argentation chromatography and used as substrates in incubations with hepatocytes isolated from trout liver. Both 14C-labelled 24:6n-3 and 22:6n-3-were produced by hepatocytes incubated with radiolabelled 24:5n-3. When hepatocytes were incubated with radiolabelled 24:6n-3, the amount of radioactivity recovered in 22:6n-3 over 6 hr increased in direct relation to the decrease observed in the amount of radioactivity recovered in 24:6n-3. The results suggest that the formation of 22:6n-3 in trout liver does not involve delta 4 desaturation of 22:5n-3 but rather proceeds via the delta 6 desaturation of 24:5n-3 with the subsequent chain shortening of the 24:6n-3 produced.

摘要

研究了24:5n-3和24:6n-3在鳟鱼肝脏中作为二十二碳六烯酸(22:6n-3)形成过程中的中间体的作用。从鳟鱼肝脏制备的微粒体将[1-14C] -二十碳五烯酸(20:5n-3)转化为24:5n-3和24:6n-3,但不能转化为二十二碳六烯酸(22:6n-3)。通过银离子色谱法从微粒体孵育物中分离出放射性标记的24:5n-3和24:6n-3,并将其用作与从鳟鱼肝脏分离的肝细胞孵育的底物。用放射性标记的24:5n-3孵育的肝细胞产生了14C标记的24:6n-3和22:6n-3。当用放射性标记的24:6n-3孵育肝细胞时,在6小时内22:6n-3中回收的放射性活度与24:6n-3中回收的放射性活度的减少直接相关。结果表明,鳟鱼肝脏中22:6n-3的形成不涉及22:5n-3的δ4去饱和,而是通过24:5n-3的δ6去饱和以及随后产生的24:6n-3的链缩短来进行。

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