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在铜(II)和抗坏血酸存在的情况下,链脲佐菌素(STZ)产生一氧化氮:对STZ诱导的糖尿病发展的影响。

Generation of nitric oxide from streptozotocin (STZ) in the presence of copper(II) plus ascorbate: implication for the development of STZ-induced diabetes.

作者信息

Tsuji A, Sakurai H

机构信息

Department of Analytical and Bioinorganic Chemistry, Kyoto Pharmaceutical University, Nakauchi-cho 5, Yamashina-ku, Misasagi, 607-0825, Japan.

出版信息

Biochem Biophys Res Commun. 1998 Apr 7;245(1):11-6. doi: 10.1006/bbrc.1998.8368.

Abstract

Streptozotocin (STZ) is widely used as a strong inducer of insulin-dependent diabetes in experimental animals. Although nitric oxide (NO) generation from STZ has been proposed to be responsible for the toxicity of pancreatic B-cells, the mechanism is yet unknown. We found that STZ generates NO in the presence of Cu(II) plus ascorbate. In addition, nicotinamide, which is an antidiabetic agent against STZ, has been found to inhibit NO generation from STZ during the reaction with Cu(II) plus ascorbate. Since rat pancreatic islets contain both ascorbate and Cu at the concentrations of 3.5 mM and 1. 0 nmol/mg protein, respectively, our present results indicate that (1>) NO generation is responsible for the development of STZ-induced diabetes and (2) mechanism for the protection of diabetes by nicotinamide is due to the inhibition of NO generation from STZ through complex formation between nicotinamide and Cu (I), which is reduced by ascorbate.

摘要

链脲佐菌素(STZ)在实验动物中被广泛用作胰岛素依赖型糖尿病的强效诱导剂。尽管有人提出STZ产生的一氧化氮(NO)是胰腺β细胞毒性的原因,但其机制尚不清楚。我们发现STZ在铜(II)加抗坏血酸存在的情况下会产生NO。此外,已发现作为抗STZ糖尿病药物的烟酰胺在与铜(II)加抗坏血酸反应期间会抑制STZ产生NO。由于大鼠胰岛中抗坏血酸和铜的浓度分别为3.5 mM和1.0 nmol/mg蛋白质,我们目前的结果表明:(1)NO的产生是STZ诱导糖尿病发展的原因;(2)烟酰胺对糖尿病的保护机制是由于烟酰胺与铜(I)形成复合物抑制了STZ产生NO,而铜(I)被抗坏血酸还原。

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