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氯化钠可促进酸胁迫下的大肠杆菌O157:H7的恢复和生长。

Sodium chloride enhances recovery and growth of acid-stressed E. coli O157:H7.

作者信息

Jordan K N, Davies K W

机构信息

Unilever Research Laboratory, Bedford, UK.

出版信息

Lett Appl Microbiol. 2001 May;32(5):312-5. doi: 10.1046/j.1472-765x.2001.00911.x.

Abstract

AIMS

Combinations of sodium chloride and acid are frequently used to inhibit growth of spoilage and pathogenic bacteria in food. The influence of differing sodium chloride, lactate and pH values on the growth of stressed and unstressed cells of a non-toxigenic strain of Escherichia coli O157:H7 was studied.

METHODS AND RESULTS

At pH 5.5 or 6.0, there was little or no effect on the growth rate in the presence of lactate and/or sodium chloride, but the lag times were longer as the lactate concentration increased. At pH 5.0, in the absence of sodium chloride, increasing the lactate concentration increased the growth rate and the lag time; no growth occurred in the presence of 1.5 g 100 g(-1) lactate. In the presence of 4-6 g 100 g(-1) sodium chloride, growth occurred at 1.5 g 100 g(-1) lactate. The growth rate was similar at all lactate concentrations.

CONCLUSION

The results demonstrate that the presence of sodium chloride promoted growth of E. coli O157:H7, especially under stressful conditions of low pH.

SIGNIFICANCE AND IMPACT OF THE STUDY

These findings could have implications for the use of acid and sodium chloride as a preservation treatment for the inhibition of E. coli O157:H7 in food.

摘要

目的

氯化钠和酸的组合常用于抑制食品中腐败菌和病原菌的生长。研究了不同氯化钠、乳酸和pH值对非产毒型大肠杆菌O157:H7应激和非应激细胞生长的影响。

方法与结果

在pH 5.5或6.0时,乳酸和/或氯化钠存在下对生长速率几乎没有影响,但随着乳酸浓度增加,延滞期延长。在pH 5.0且无氯化钠时,增加乳酸浓度会提高生长速率和延长延滞期;在乳酸浓度为1.5 g/100 g时不生长。在氯化钠浓度为4 - 6 g/100 g时,乳酸浓度为1.5 g/100 g时可生长。所有乳酸浓度下生长速率相似。

结论

结果表明氯化钠的存在促进了大肠杆菌O157:H7的生长,尤其是在低pH的应激条件下。

研究的意义和影响

这些发现可能对使用酸和氯化钠作为抑制食品中大肠杆菌O157:H7的保鲜处理有影响。

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