Baird S J E, Barton N H, Etheridge A M
Museum of Vertebrate Zoology, UC Berkeley, 3101 Valley Life Sciences Building, Berkeley, CA 94720-3160, USA.
Theor Popul Biol. 2003 Dec;64(4):451-71. doi: 10.1016/s0040-5809(03)00098-4.
What is the chance that some part of a stretch of genome will survive? In a population of constant size, and with no selection, the probability of survival of some part of a stretch of map length y < 1 approaches y/log(yt/2) for log(yt) > or = 1. Thus, the whole genome is certain to be lost, but the rate of loss is extremely slow. This solution extends to give the whole distribution of surviving block sizes as a function of time. We show that the expected number of blocks at time t is 1+yt and give expressions for the moments of the number of blocks and the total amount of genome that survives for a given time. The solution is based on a branching process and assumes complete interference between crossovers, so that each descendant carries only a single block of ancestral material. We consider cases where most individuals carry multiple blocks, either because there are multiple crossovers in a long genetic map, or because enough time has passed that most individuals in the population are related to each other. For species such as ours, which have a long genetic map, the genome of any individual which leaves descendants (approximately 80% of the population for a Poisson offspring number with mean two) is likely to persist for an extremely long time, in the form of a few short blocks of genome.
一段基因组的某些部分得以留存的概率是多少?在一个规模恒定且无选择作用的种群中,对于长度(y\lt1)的一段图谱长度,当(\log(yt)\geq1)时,其某些部分留存的概率趋近于(y / \log(yt / 2))。因此,整个基因组肯定会丢失,但丢失的速率极其缓慢。这个解决方案可扩展以给出存活片段大小随时间变化的完整分布。我们表明,在时间(t)时片段的预期数量为(1 + yt),并给出了片段数量的矩以及在给定时间内存活的基因组总量的表达式。该解决方案基于一个分支过程,并假设交叉之间存在完全干扰,这样每个后代仅携带单个祖先物质块。我们考虑了大多数个体携带多个片段的情况,这要么是因为在长遗传图谱中有多个交叉,要么是因为经过了足够长的时间,以至于种群中的大多数个体彼此相关。对于像我们这样具有长遗传图谱的物种,任何留下后代的个体(对于平均后代数量为两个的泊松后代数量,约占种群的(80%))的基因组可能会以几个短基因组片段的形式持续极长的时间。