Fagiolino P, Savio E, Stareczek S
Laboratorio de Farmacodinamia, Facultad de Química, Montevideo, Uruguay.
Eur J Drug Metab Pharmacokinet. 1991;Spec No 3:485-96.
The elimination rate of drug from a capacity-limited one-compartment model can be expressed by equation (1): [formula: see text] Traditionally equation (1) was linearized according to equation (2): [formula: see text] Here, an alternative linear relationships between concentration and the area under the curve of C/(Km + c]) is proposed: [formula: see text] By iteration of Km into equation (3) until the statistic of analysis of variance for the regression is maximized, both Km and Vmax can be obtained. Several cases were considered: a) Intravenous bolus (single dose): Km (mg/L), Vmax (mg/L h), Vd (L) and V (mg/h) can be estimated. b) Extravascular administration (single dose): by the method of residuals it is possible to make additional estimations of FD/Vd (mg/L) and Ka (1/h). c) Bioequivalence studies: with parameters obtained at single dose, the simulated levels at steady-state are considered for the bioequivalence assessments. d) Km, Vmax estimation with two (C,t) points (single dose): double iteration (Km values and interpolated fictitious third points) are needed. e) Multiple dose: [formula: see text] If t2-t1 = T (interval of administration) it is possible to calculate operatives Km, Vmax, FD/Vd and to estimate Css (steady-state concentration). C1 and C2 correspond to different intervals. All the areas were calculated by the trapezoidal rule.
药物从容量限制的单室模型中的消除速率可用方程(1)表示:[公式:见正文] 传统上,方程(1)是根据方程(2)线性化的:[公式:见正文] 在此,提出了浓度与C/(Km + c)曲线下面积之间的另一种线性关系:[公式:见正文] 通过将Km代入方程(3)进行迭代,直到回归方差分析的统计量最大化,就可以得到Km和Vmax。考虑了几种情况:a)静脉推注(单剂量):可以估计Km(mg/L)、Vmax(mg/L·h)、Vd(L)和V(mg/h)。b)血管外给药(单剂量):通过残差法可以进一步估计FD/Vd(mg/L)和Ka(1/h)。c)生物等效性研究:利用单剂量获得的参数,考虑稳态下的模拟水平进行生物等效性评估。d)用两个(C,t)点估计Km、Vmax(单剂量):需要双重迭代(Km值和内插的虚拟第三点)。e)多剂量:[公式:见正文] 如果t2 - t1 = T(给药间隔),则可以计算有效Km、Vmax、FD/Vd并估计Css(稳态浓度)。C1和C2对应不同的间隔。所有面积均通过梯形法则计算。