Linari M, Piazzesi G, Lombardi V
Laboratorio di Fisiologia, Dipartimento di Biologia Evoluzionistica, Università di Firenze, Sesto Fiorentino, Firenze, Italy.
Biophys J. 2009 Jan;96(2):583-92. doi: 10.1016/j.bpj.2008.09.026.
We use the inhibitor of isometric force of skeletal muscle N-benzyl-p-toluene sulfonamide (BTS) to decrease, in a dose dependent way, the number of myosin motors attached to actin during the steady isometric contraction of single fibers from frog skeletal muscle (4 degrees C, 2.1 microm sarcomere length). In this way we can reduce the strain in the myofilament compliance during the isometric tetanus (T(0)) from 3.54 nm in the control solution (T(0,NR)) to approximately 0.5 nm in 1 microM BTS, where T(0) is reduced to approximately 0.15 T(0,NR). The quick force recovery after a step release (1-3 nm per half-sarcomere) becomes faster with the increase of BTS concentration and the decrease of T(0). The simulation of quick force recovery with a multistate model of force generation, that adapts Huxley and Simmons model to account for both the high stiffness of the myosin motor (approximately 3 pN/nm) and the myofilament compliance, shows that the increase in the rate of quick force recovery by BTS is explained by the reduced strain in the myofilaments, consequent to the decrease in half-sarcomere force. The model estimates that i), for the same half-sarcomere release the state transition kinetics in the myosin motor are five times faster in the absence of filament compliance than in the control; and ii), the rate of force recovery from zero to T(0) is approximately 6000/s in the absence of filament compliance.
我们使用骨骼肌等长力抑制剂N-苄基对甲苯磺酰胺(BTS),以剂量依赖的方式减少青蛙骨骼肌单纤维在稳定等长收缩(4摄氏度,肌节长度2.1微米)过程中附着于肌动蛋白的肌球蛋白马达数量。通过这种方式,我们可以将等长强直收缩(T(0))期间肌丝顺应性的应变从对照溶液(T(0,NR))中的3.54纳米降低到1微摩尔BTS中的约0.5纳米,此时T(0)降低至约0.15 T(0,NR)。在半肌节进行阶跃释放(每半肌节1 - 3纳米)后,快速力恢复随着BTS浓度的增加和T(0)的降低而加快。使用力产生的多状态模型模拟快速力恢复,该模型采用赫胥黎和西蒙斯模型来考虑肌球蛋白马达的高刚度(约3皮牛/纳米)和肌丝顺应性,结果表明BTS使快速力恢复速率增加是由于半肌节力降低导致肌丝应变减小所致。该模型估计,i)对于相同的半肌节释放,在没有肌丝顺应性的情况下,肌球蛋白马达中的状态转变动力学比对照快五倍;ii)在没有肌丝顺应性的情况下,从零到T(0)的力恢复速率约为6000/秒。