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在两个电子转移过程中,能量在黄素酶分子水平释放的机制。

The mechanism by which the energy is released at the level of the flavoenzyme molecule during the transfer of two electrons.

作者信息

Portelli C

出版信息

Physiologie. 1977 Oct-Dec;14(4):297-301.

PMID:201952
Abstract

The model of a mechanism producing the excitation of two electrons by the rotation of an orbital is presented functioning at the level of the flavoenzyme molecule. According to this model, during the transfer of two electrons from an NADH coenzyme to a flavoenzyme molecule, in a reaction cavity of the flavoprotein, two (Fe2+:S) covalent bonds are formed. Subsequently to the electric polarization induced by the formation of some intermolecular connections and by some fixed ions, and (Fe2+:S) orbital turns with an angle, having the nucleus of the sulfur atom as a pivot point, in such a way that an (Fe2+) ions is left out from the covalent bond, and it is replaced by a proton (released from a water molecule). A new (S:H) orbital is formed. Within this (S:H) orbital, the proton moves towards the nucleus of the sulfur atom, from 2.10 A degrees internuclear distance (position in which the proton was included by the orbital rotation) to 1.36 A degrees internuclear distance--corresponding to the length of the (S:H) covalent bond. By the proton movement, the two electrons of the (S:H) orbital arrive on an excitation state level. Then, they fall to their fundamental level and deliver two quanta of electronic excitation, which are transmitted further and help the synthesis of an ATP molecule.

摘要

提出了一种通过轨道旋转激发两个电子的机制模型,该模型在黄素酶分子水平上起作用。根据该模型,在两个电子从NADH辅酶转移到黄素酶分子的过程中,在黄素蛋白的反应腔中形成了两个(Fe2 +:S)共价键。在由一些分子间连接和一些固定离子的形成所引起的电极化之后,(Fe2 +:S)轨道以硫原子的原子核为枢轴点旋转一定角度,使得一个(Fe2 +)离子从共价键中脱离,并用一个质子(从水分子中释放)取代它。形成了一个新的(S:H)轨道。在这个(S:H)轨道内,质子从2.10埃的核间距(质子通过轨道旋转被包含在其中的位置)向硫原子的原子核移动到1.36埃的核间距,这对应于(S:H)共价键的长度。通过质子的移动,(S:H)轨道的两个电子达到激发态水平。然后,它们落到基态并释放两个电子激发量子,这些量子被进一步传递并有助于ATP分子的合成。

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