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基于 ESAT-6 和 CFP-10 重组抗原的免疫诊断在巴西东北部流行地区儿童结核病中的应用。

Immunological diagnosis of tuberculosis based on recombinant antigens ESAT-6 and CFP-10 in children from an endemic area in northeast Brazil.

机构信息

Aggeu Magalhães Research Center-Oswaldo Cruz Institute (FIOCRUZ), Department of Immunology, Av. Moares Rego s/n, Recife, Pernambuco, Brazil.

出版信息

Scand J Immunol. 2010 Nov;72(5):460-8. doi: 10.1111/j.1365-3083.2010.02459.x.

Abstract

Diagnostic tests for tuberculosis (TB) using interferon gamma (IFN-γ) responses produced by T lymphocytes after stimulation by early secretory antigen target 6 (ESAT-6), culture filtrate protein 10 (CFP-10) or purified protein derivate (PPD) were carried out using ELISA (enzyme-linked immunosorbent assay) in whole blood culture supernatants from children with suspected TB disease (n=21), latent TB infection (LTBI; n=17) and negative controls (NC; n=21) from Recife, Pernambuco, Brazil. The results were analysed using the ROC (receiver operating characteristic) curves and the areas under the curve (AUC) generated varied from 0.5 to 1.0 with higher values indicating increased discriminatory ability. Comparisons of AUCs were made using non-parametric assumptions, and the differences were considered significant if P<0.05. The ROC curve showed a statistical difference (P = 0.015) between the LTBI and NC groups with an AUC of 0.731, TB disease and NC (AUC=0.780; P=0.002) and a group with TB (latent infection+disease, n=38) and NC (AUC=0.758; P = 0.001) when the antigen used was ESAT-6. No statistical difference was found between the groups when CFP-10 or PPD was used. In conclusion, the ESAT-6 test may be the most appropriate for diagnosis of childhood TB, both LTBI and TB disease, when associated with epidemiological and clinical data, especially in endemic areas such as Brazil.

摘要

采用酶联免疫吸附试验(ELISA)检测方法,以全血培养上清液为检测标本,检测巴西累西腓市疑似结核病患儿(n=21)、潜伏性结核感染(LTBI;n=17)和阴性对照者(NC;n=21)的干扰素-γ(IFN-γ)反应,这些反应是由 T 淋巴细胞在受到早期分泌抗原靶 6(ESAT-6)、培养滤液蛋白 10(CFP-10)或纯化蛋白衍生物(PPD)刺激后产生的。采用受试者工作特征(ROC)曲线分析结果,曲线下面积(AUC)为 0.5-1.0,AUC 值越高,提示诊断能力越强。ROC 曲线分析显示,在 LTBI 组与 NC 组(AUC=0.731,P=0.015)、TB 病组与 NC 组(AUC=0.780,P=0.002)以及潜伏感染+TB 病组(n=38)与 NC 组(AUC=0.758,P=0.001)中,ESAT-6 抗原检测的 AUC 存在统计学差异,而在 CFP-10 抗原或 PPD 抗原检测中,各组间 AUC 无统计学差异。当与流行病学和临床数据相结合时,尤其是在巴西等流行地区,ESAT-6 检测可能是诊断儿童 LTBI 和 TB 病的最佳方法。

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