正常颈项透明层厚度的分布：泰国的一项多中心研究。

Distribution of normal nuchal translucency thickness: a multicenter study in Thailand.

机构信息

Department of Obstetrics and Gynecology, Faculty of Medicine, Prince of Songkla University, Songkhla, Thailand.

出版信息

Gynecol Obstet Invest. 2011;71(2):124-8. doi: 10.1159/000320754. Epub 2010 Dec 9.

DOI:10.1159/000320754

PMID:21150163

Abstract

AIMS

To establish the normative data distribution of nuchal translucency (NT) thickness in Thai fetuses.

METHODS

A cross-sectional multicenter study was conducted among 6,455 women with singleton pregnancies and gestational age between 10 and 14 weeks. For each case, the fetal crown-rump length (CRL) and NT were measured by transabdominal ultrasound. Transvaginal ultrasounds were used in poorly visualized cases. The distribution values of the NT thicknesses and their corresponding 10-mm CRL intervals between 45 and 84 mm were examined to obtain the median and 95th percentiles. Quantile regression modeling across the CRLs was performed to obtain the reference values.

RESULTS

Transabdominal ultrasound measurements were successfully done on 6,347 fetuses with 39 cases by the transvaginal route. Fetuses with CRL between 45 and 84 mm and normal outcomes made up a total of 4,352 cases. The mean (SD) gestational age, CRL and NT thickness were 12.5 (0.7) weeks, 60.2 (9.7) mm, and 1.15 (0.38) mm, respectively. The mean normal NT increased linearly with CRL. The quantile regression equation to predict the 95th percentile of the NT thickness (mm) was 0.727 + [0.017 × CRL (mm)].

CONCLUSIONS

The NT thickness in normal Thai fetuses was found to be thinner than in both Caucasian and other Asian populations.

摘要

目的

建立泰国胎儿颈项透明层（NT）厚度的正常参考值分布。

方法

这是一项多中心、横断面研究，共纳入了 6455 名单胎妊娠且孕龄为 10-14 周的孕妇。对每例孕妇，均通过经腹部超声测量胎儿头臀长（CRL）和 NT。对于经腹部超声显示不佳的孕妇，采用经阴道超声。对 45-84mm 范围内、每 10mm CRL 间隔的 NT 厚度分布值进行检查，以获得中位数和 95%百分位数。对 CRL 进行分位数回归建模，以获得参考值。

结果

6347 例胎儿经腹部超声成功测量，39 例经阴道超声测量。共纳入 4352 例 CRL 正常且结局正常的孕妇。平均（标准差）孕龄、CRL 和 NT 厚度分别为 12.5（0.7）周、60.2（9.7）mm 和 1.15（0.38）mm。正常 NT 厚度随 CRL 呈线性增加。预测 NT 厚度（mm）第 95 百分位数的分位数回归方程为 0.727+[0.017×CRL（mm）]。