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双[四水合-(1,10-菲咯啉-κN,N')钴(II)]六水合钴(II)双[3,5-双-(羧基甲氧基)苯甲酸酯]四水合物

Bis[tetra-aqua-(1,10-phenanthroline-κN,N')cobalt(II)] hexa-aqua-cobalt(II) bis-[3,5-bis-(carboxyl-atometh-oxy)benzoate] tetra-hydrate.

作者信息

Song Hui-Ying, Wang Xiao-Juan, Qiu Shi-Zhen, Feng Yun-Long

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2010 Nov 17;66(Pt 12):m1577-8. doi: 10.1107/S1600536810046386.

DOI:10.1107/S1600536810046386
PMID:21589263
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC3011475/
Abstract

The title compound, Co(C(12)H(8)N(2))(H(2)O)(4)Co(H(2)O)(6)(2)·4H(2)O, was obtanied by the reaction of cobalt acetate with 3,5-bis-(carb-oxy-meth-oxy)benzoic acid and 1,10-phenanthroline. The asymmetric unit contains one tetra-aqua-(1,10-phenanthroline)cobalt(II) cation, one half of a hexa-aqua-cobalt(II) cation that is completed by inversion symmetry, one 3,5-bis-(carboxyl-atometh-oxy)benzoate trianion and two lattice water mol-ecules. The two Co(II) atoms each show a slightly distorted octa-hedral coordination (CoO(6) and CoO(4)N(2)). The cations, anions and lattice water mol-ecules are linked by an intricate network of O-H⋯O hydrogen bonds into a three-dimensional structure.

摘要

标题化合物[Co(C₁₂H₈N₂)(H₂O)₄]₂Co(H₂O)₆₂·4H₂O是通过醋酸钴与3,5-双（羧基甲氧基）苯甲酸和1,10-菲咯啉反应得到的。不对称单元包含一个四水合（1,10-菲咯啉）钴（II）阳离子、一个通过反演对称性完成的六水合钴（II）阳离子的一半、一个3,5-双（羧基甲氧基）苯甲酸根三阴离子和两个晶格水分子。两个Co（II）原子均呈现出略微扭曲的八面体配位（CoO₆和CoO₄N₂）。阳离子、阴离子和晶格水分子通过复杂的O-H⋯O氢键网络连接成三维结构。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/adf8/3011475/5b49088772c9/e-66-m1577-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/adf8/3011475/11f2cbaa0d56/e-66-m1577-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/adf8/3011475/5b49088772c9/e-66-m1577-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/adf8/3011475/11f2cbaa0d56/e-66-m1577-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/adf8/3011475/5b49088772c9/e-66-m1577-fig2.jpg

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