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维生素 E 缺乏会降低斑马鱼(Danio rerio)中的长链多不饱和脂肪酸。

Vitamin E deficiency decreases long-chain PUFA in zebrafish (Danio rerio).

机构信息

Linus Pauling Institute, Oregon State University, Corvallis, OR, USA.

出版信息

J Nutr. 2011 Dec;141(12):2113-8. doi: 10.3945/jn.111.144279. Epub 2011 Oct 19.

Abstract

α-Tocopherol is a required, lipid-soluble antioxidant that protects PUFA. We hypothesized that α-tocopherol deficiency in zebrafish compromises PUFA status. Zebrafish were fed for 1 y either an α-tocopherol-sufficient (E+; 500 mg α-tocopherol/kg) or -deficient (E-; 1.1 mg α-tocopherol/kg) diet containing α-linolenic (ALA) and linoleic (LA) acids but without arachidonic acid (ARA), EPA, or DHA. Vitamin E deficiency in zebrafish decreased by ~20% (n-6) (P < 0.05) and (n-3) (P < 0.05) PUFA and increased the (n-6):(n-3) PUFA ratio (P < 0.05). In E- compared to E+ females, long chain-PUFA status was impaired, as assessed by a ~60% lower DHA:ALA ratio (P < 0.05) and a ~50% lower ARA:LA ratio (P < 0.05). fads2 (P < 0.05) and elovl2 (P < 0.05) mRNA expression was doubled in E- compared to E+ fish. Thus, inadequate vitamin E status led to a depletion of PUFA that may be a result of either or both increased lipid peroxidation and an impaired ability to synthesize sufficient PUFA, especially (n-3) PUFA.

摘要

α-生育酚是一种必需的脂溶性抗氧化剂,可保护多不饱和脂肪酸。我们假设,斑马鱼缺乏α-生育酚会损害多不饱和脂肪酸的状态。斑马鱼被喂食了 1 年的 α-生育酚充足(E+;500mgα-生育酚/千克)或缺乏(E-;1.1mgα-生育酚/千克)饮食,其中含有α-亚麻酸(ALA)和亚油酸(LA),但不含花生四烯酸(ARA)、EPA 或 DHA。斑马鱼的维生素 E 缺乏症降低了约 20%(n-6)(P<0.05)和(n-3)(P<0.05)多不饱和脂肪酸,并增加了(n-6):(n-3)多不饱和脂肪酸的比例(P<0.05)。与 E+组相比,E-组雌性鱼的长链多不饱和脂肪酸状态受损,这表现为 DHA:ALA 比值降低了约 60%(P<0.05)和 ARA:LA 比值降低了约 50%(P<0.05)。与 E+组相比,E-组的 fads2(P<0.05)和 elovl2(P<0.05)mRNA 表达增加了一倍。因此,维生素 E 状况不足导致多不饱和脂肪酸的消耗,这可能是由于脂质过氧化增加和合成足够多不饱和脂肪酸的能力受损,特别是(n-3)多不饱和脂肪酸。

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