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Q(ST)与 F(ST)之间的比较——我们之前误解了多少?

Comparisons between Q(ST) and F(ST) --how wrong have we been?

机构信息

Estación Biológica de Doñana (EBD-CSIC). Avda. Américo Vespucio s/n, Sevilla E-41092, Spain.

出版信息

Mol Ecol. 2011 Dec;20(23):4830-9. doi: 10.1111/j.1365-294X.2011.05333.x. Epub 2011 Nov 8.

DOI:10.1111/j.1365-294X.2011.05333.x
PMID:22060729
Abstract

The comparison between quantitative genetic divergence (Q(ST) ) and neutral genetic divergence (F(ST) ) among populations has become the standard test for historical signatures of selection on quantitative traits. However, when the mutation rate of neutral markers is relatively high in comparison with gene flow, estimates of F(ST) will decrease, resulting in upwardly biased comparisons of Q(ST) vs. F(ST) . Reviewing empirical studies, the difference between Q(ST) and F(ST) is positively related to marker heterozygosity. After refuting alternative explanations for this pattern, we conclude that marker mutation rate indeed has had a biasing effect on published Q(ST) -F(ST) comparisons. Hence, it is no longer clear that populations have commonly diverged in response to divergent selection. We present and discuss potential solutions to this bias. Comparing Q(ST) with recent indices of neutral divergence that statistically correct for marker heterozygosity (Hedrick's G'st and Jost's D) is not advised, because these indices are not theoretically equivalent to Q(ST) . One valid solution is to estimate F(ST) from neutral markers with mutation rates comparable to those of the loci underlying quantitative traits (e.g. SNPs). Q(ST) can also be compared to Φ(ST) (Phi(ST) ) of amova, as long as the genetic distance among allelic variants used to estimate Φ(ST) reflects evolutionary history: in that case, neutral divergence is independent of mutation rate. In contrast to their common usage in comparisons of Q(ST) and F(ST) , microsatellites typically have high mutation rates and do not evolve according to a simple evolutionary model, so are best avoided in Q(ST) -F(ST) comparisons.

摘要

种群间数量遗传分化 (Q(ST) ) 与中性遗传分化 (F(ST) ) 的比较已成为选择对数量性状历史影响的标准检验。然而,当中性标记的突变率相对于基因流较高时,F(ST) 的估计值将会降低,从而导致 Q(ST) 与 F(ST) 的比较出现向上偏差。在回顾了实证研究后,Q(ST) 与 F(ST) 之间的差异与标记杂合度呈正相关。在驳斥了这种模式的替代解释后,我们得出结论,标记突变率确实对已发表的 Q(ST) -F(ST) 比较产生了偏差影响。因此,种群是否普遍因分歧选择而发生分歧已不再明确。我们提出并讨论了这种偏差的潜在解决方案。不建议将 Q(ST) 与最近的中性分化指数(如 Hedrick 的 G'st 和 Jost 的 D)进行比较,因为这些指数在理论上与 Q(ST) 并不等效。一个有效的解决方案是从与数量性状相关的基因座具有可比突变率的中性标记中估计 F(ST) (例如 SNP)。只要用于估计 Φ(ST) 的等位变异之间的遗传距离反映了进化历史,也可以将 Q(ST) 与 AMOVA 的 Φ(ST) (Phi(ST) )进行比较:在这种情况下,中性分化独立于突变率。与在 Q(ST) 和 F(ST) 比较中常见的用法不同,微卫星通常具有较高的突变率,并且其进化不符合简单的进化模型,因此在 Q(ST) -F(ST) 比较中最好避免使用微卫星。

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