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μ-（3,4,5,6,7-η：1,9,10,11,12）-5,11-二叔丁基-2,2,8,8-四甲基-2,8-二硅杂三环-[7.3.0.0（3,7）]十二碳四烯二基]双-[二羰基钌（I）]

μ-(3,4,5,6,7-η:1,9,10,11,12)-5,11-Di-tert-butyl-2,2,8,8-tetra-methyl-2,8-disila-tricyclo-[7.3.0.0(3,7)]dodeca-tetra-enedi-yl]bis-[dicarbonyl-ruthenium(I).

作者信息

Zhu Bolin

机构信息

College of Chemistry and Tianjin Key Laboratory of Structure and Performance for Functional Molecules, Tianjin Normal University, Tianjin 300387, People's Republic of China.

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2012 Sep 1;68(Pt 9):m1164. doi: 10.1107/S1600536812033454. Epub 2012 Aug 11.

DOI:10.1107/S1600536812033454
PMID:22969461
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC3435588/
Abstract

The title compound, [Ru(2)(C(22)H(34)Si(2))(CO)(4)], contains two Ru(I) atoms linked by a bridging (η(5)-(t)BuC(5)H(2))(2)(SiMe(2))(2) ligand ((t)Bu is a tert-butyl and Me is a methyl group) with an Ru-Ru bond length of 2.8401 (7) Å. The dihedral angle between the planes of the cyclo-penta-dienyl rings of the ligand is 123.13 (19)°. The four terminal carbonyl ligands are bound in a symmetrical and staggered array. In the crystal, mol-ecules are linked via pairs of C-H⋯O hydrogen bonds, forming inversion dimers.

摘要

标题化合物[Ru₂(C₂₂H₃₄Si₂)(CO)₄]包含两个通过桥连的(η⁵-(t)BuC₅H₂)₂(SiMe₂)₂配体连接的Ru(I)原子（(t)Bu为叔丁基，Me为甲基），Ru-Ru键长为2.8401(7) Å。配体的环戊二烯基环平面之间的二面角为123.13(19)°。四个末端羰基配体以对称且交错的排列方式键合。在晶体中，分子通过成对的C-H⋯O氢键相连，形成倒转二聚体。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/886c/3435588/f906b998a6ec/e-68-m1164-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/886c/3435588/f906b998a6ec/e-68-m1164-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/886c/3435588/f906b998a6ec/e-68-m1164-fig1.jpg

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本文引用的文献

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