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双链 DNA 中的过剩电子俘获:通过堆积腺嘌呤的远程转移。

Excess electron trapping in duplex DNA: long range transfer via stacked adenines.

机构信息

Department of Biochemistry and Biophysics, University of Rochester, Rochester, New York 14642, USA.

出版信息

J Phys Chem B. 2012 Nov 8;116(44):13211-8. doi: 10.1021/jp307851g. Epub 2012 Oct 24.

Abstract

An understanding of charge transfer (CT) in DNA lies at the root of assessing the risks and benefits of exposure to ionizing radiation. Energy deposition by high-energy photons and fast-charged particles creates holes and excess electrons (EEs) in DNA, and the subsequent reactions determine the complexity of DNA damage and ultimately the risk of disease. Further interest in CT comes from the possibility that hole transfer, excess electron transfer (EET), or both in DNA might be used to develop nanoscale circuits. To study EET in DNA, EPR spectroscopy was used to determine the distribution of EE trapping by oligodeoxynucleotides irradiated and observed at 4 K. Our results indicate that stretches of consecutive adenine bases on the same strand serve as an ideal conduit for intrastrand EET in duplex DNA at 4 K. Specifically, we show that A is an efficient trap for EE at 4 K if, and only if, the A strand of the duplex does not contain one of the other three bases. If there is a T, C, or G on the A strand, then trapping occurs at T or C instead of A. This holds true for stretches up to 32 A's. Whereas T competes effectively against A for the EE, it does not compete effectively against C. Long stretches of T pass the majority of EE to C. Our results show that AT stretches channel EE to cytosine, an end point with significance to both radiation damage and the photochemical repair of pyrimidine dimers.

摘要

理解 DNA 中的电荷转移(CT)是评估暴露于电离辐射的风险和益处的基础。高能光子和高速带电粒子的能量沉积会在 DNA 中产生空穴和过剩电子(EEs),随后的反应决定了 DNA 损伤的复杂性,并最终决定了疾病的风险。对 CT 的进一步兴趣来自于这样一种可能性,即 DNA 中的空穴转移、过剩电子转移(EET)或两者都可能用于开发纳米级电路。为了研究 DNA 中的 EET,使用电子顺磁共振(EPR)光谱来确定寡脱氧核苷酸在 4 K 下辐照和观察时 EE 捕获的分布。我们的结果表明,在 4 K 下,双链 DNA 中同一链上连续的腺嘌呤碱基链段是进行链内 EET 的理想通道。具体来说,我们表明,如果并且只有在双链的 A 链中不包含其他三个碱基中的一个,那么 A 是在 4 K 时 EE 的有效陷阱。如果 A 链上有 T、C 或 G,则会在 T 或 C 处而不是在 A 处发生捕获。这适用于长达 32 个 A 的链段。虽然 T 可以有效地与 EE 竞争 A,但它不能有效地与 C 竞争。长的 T 链段将大多数 EE 传递给 C。我们的结果表明,AT 链段将 EE 引导到胞嘧啶,这对辐射损伤和嘧啶二聚体的光化学修复都具有重要意义。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/3823/3546541/2a8c90198d5c/nihms417545f1.jpg

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