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关于菲、芴和9-芴酮生成二苯并呋喃的机理研究。

Mechanistic studies on the dibenzofuran formation from phenanthrene, fluorene and 9-fluorenone.

作者信息

Li Shanqing, Zhang Qingzhu

机构信息

Environment Research Institute, Shandong University, Jinan 250100, China.

出版信息

Int J Mol Sci. 2015 Mar 6;16(3):5271-84. doi: 10.3390/ijms16035271.

Abstract

We carried out molecular orbital theory calculations for the homogeneous gas-phase formation of dibenzofuran from phenanthrene, fluorene, 9-methylfluorene and 9-fluorenone. Dibenzofuran will be formed if ∙OH adds to C8a, and the order of reactivity follows as 9-fluorenone > 9-methylfluorene > fluorene > phenanthrene. The oxidations initiated by ClO∙ are more favorable processes, considering that the standard reaction Gibbs energies are at least 21.63 kcal/mol lower than those of the equivalent reactions initiated by ∙OH. The adding of ∙OH and then O2 to phenanthrene is a more favorable route than adding ∙OH to C8a of phenanthrene, when considering the greater reaction extent. The reaction channel from fluorene and O2 to 9-fluorenone and H2O seems very important, not only because it contains only three elementary reactions, but because the standard reaction Gibbs energies are lower than -80.07 kcal/mol.

摘要

我们对菲、芴、9-甲基芴和9-芴酮在均相气相中生成二苯并呋喃的过程进行了分子轨道理论计算。如果∙OH加成到C8a上,就会生成二苯并呋喃,其反应活性顺序为9-芴酮>9-甲基芴>芴>菲。考虑到标准反应吉布斯自由能比由∙OH引发的等效反应至少低21.63 kcal/mol,由ClO∙引发的氧化反应是更有利的过程。当考虑到更大的反应程度时,对于菲而言,先加∙OH然后加O2比将∙OH加成到菲的C8a上是更有利的途径。从芴和O2到9-芴酮和H2O的反应通道似乎非常重要,这不仅是因为它只包含三个基元反应,还因为标准反应吉布斯自由能低于-80.07 kcal/mol。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/7766/4394475/7d78ba4326d1/ijms-16-05271-g004.jpg

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