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一个大的内部缺失将酵母LEU3转化为组成型转录激活因子。

A large internal deletion converts yeast LEU3 to a constitutive transcriptional activator.

作者信息

Friden P, Reynolds C, Schimmel P

机构信息

Department of Biology, Massachusetts Institute of Technology, Cambridge 02139.

出版信息

Mol Cell Biol. 1989 Sep;9(9):4056-60. doi: 10.1128/mcb.9.9.4056-4060.1989.

Abstract

LEU3 of Saccharomyces cerevisiae encodes an 886-amino-acid polypeptide that activates transcription of at least five genes by binding to an upstream decanucleotide sequence. This activation is dependent on the inducer alpha-isopropylmalate, the synthesis of which is repressed by leucine. We created a 285-amino-acid LEU3 derivative by removing a large block of internal sequences, including a dense cluster of acidic residues. This deletion protein bound to the decanucleotide sequence in vitro and activated gene expression in vivo. In contrast to wild-type LEU3, the truncated LEU3 protein was an effective transcriptional activator when alpha-isopropylmalate synthesis was repressed by leucine.

摘要

酿酒酵母的LEU3编码一个886个氨基酸的多肽,该多肽通过与上游十核苷酸序列结合来激活至少五个基因的转录。这种激活依赖于诱导剂α-异丙基苹果酸,其合成受亮氨酸抑制。我们通过去除一大段内部序列(包括密集的酸性残基簇)创建了一个285个氨基酸的LEU3衍生物。这种缺失蛋白在体外与十核苷酸序列结合,并在体内激活基因表达。与野生型LEU3不同,当α-异丙基苹果酸的合成被亮氨酸抑制时,截短的LEU3蛋白是一种有效的转录激活剂。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/dc94/362471/57af5deec82b/molcellb00057-0477-a.jpg

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