Alexandrou Athanasios, Tenbergen Klaus, Adhikari Diganta
Jordan College of Agricultural Sciences and Technology, California State University-Fresno, Fresno, CA 93710, USA.
Foods. 2013 Mar 28;2(2):132-142. doi: 10.3390/foods2020132.
Today's agriculture provides an ever increasing population with sufficient quantities of food. During food production, processing, handling and transportation, an amount of energy is invested into the various products. An energy analysis of a typical American diet provides policy makers, farmers and the public with the necessary information to evaluate and make informed decisions as to how to improve the efficient use of energy. At the same time, an informed consumer may become energy conscious and be able to make dietary choices based on food energy balance. This paper studies the energy sequestered in a typical American diet as defined in Food and Agriculture Organization of the United Nations, Statistics Division (FAOSTAT). The amount of energy incorporated in this diet of 3628 kcal (15.18 MJ) per person and day to produce, transport, handle and process the foods is calculated and found to have approximately 39.92 GJ (9.54 Gcal) sequestered per person and year. It is shown that a diet in line with the United States Department of Agriculture (USDA) recommendation of around 2100 kcal (8.79 MJ) per day person will result in a reduction of energy inputs by 42% on an annual basis. This reduction for the whole population of the United States of America (USA), corresponds to approximately 879 million barrels of oil equivalent (boe) savings. Energy efficiency for the food categories studied varies from 3.4% to 56.5% with an average of 21.7%. Food energy efficiency can be further improved in some food categories through either a reduction of energy inputs or yield increase.
当今的农业为不断增长的人口提供了充足的食物。在粮食生产、加工、处理和运输过程中,会投入一定量的能源到各类产品中。对典型美国饮食进行能源分析,可为政策制定者、农民和公众提供必要信息,以便评估并就是否以及如何提高能源利用效率做出明智决策。同时,明智的消费者可能会意识到能源问题,并能够基于食物能量平衡做出饮食选择。本文研究了联合国粮食及农业组织统计司(FAOSTAT)所定义的典型美国饮食中所固存的能量。计算得出,这种人均每日3628千卡(15.18兆焦耳)的饮食在生产、运输、处理和加工食物过程中所包含的能量约为每人每年固存39.92吉焦(9.54吉卡)。研究表明,符合美国农业部(USDA)建议的人均每日约2100千卡(8.79兆焦耳)的饮食,将使能源投入每年减少42%。这对于美利坚合众国(美国)全体人口而言,相当于节省约8.79亿桶石油当量(boe)。所研究的各类食物的能源效率在3.4%至56.5%之间,平均为21.7%。通过减少能源投入或提高产量,某些食物类别的食物能源效率可以进一步提高。