Ko Jae-Hoon, Baek Jin Yang, Peck Kyong Ran, Cho Sun Young, Ha Young Eun, Kim So Hyun, Huh Hee Jae, Lee Nam Yong, Kang Cheol-In, Chung Doo Ryeon, Song Jae-Hoon
Division of Infectious Diseases, Samsung Medical Center, Sungkyunkwan University School of Medicine, 81 Irwon-ro, Gangnam-gu, Seoul 06351, Republic of Korea.
Present address: Division of Infectious Diseases, Department of Internal Medicine, Armed Forces Capital Hospital, Seongnam, Republic of Korea.
J Med Microbiol. 2017 Oct;66(10):1448-1450. doi: 10.1099/jmm.0.000583. Epub 2017 Sep 12.
Because we experienced gentamicin failure in Klebsiella pneumoniae bacteraemia that was susceptible to gentamicin despite amikacin resistance, as determined by VITEK 2, we evaluated the true susceptibility and mechanism of resistance. We screened 2818 K. pneumoniae isolates during a 1-year period at a university hospital and reviewed anti-microbial susceptibility reports using the VITEK 2 system. The minimum inhibitory concentration was substantiated by broth microdilution (BMD), and the presence of 16S rRNA methylase genes and aminoglycoside-modifying enzymes was also investigated. A total of 131 amikacin-resistant isolates from 19 patients were gentamicin non-resistant according to the VITEK 2 system. Among these, we were able to collect isolates from 12 patients (63.2 %), and a single isolate from each patient was tested. Eleven of the gentamicin non-resistant isolates (91.7 %) showed high-level resistance to both amikacin and gentamicin by BMD in association with the armA gene. Gentamicin is not an adequate treatment option for amikacin-resistant K. pneumoniae, even if VITEK 2 reports susceptibility.
由于我们在肺炎克雷伯菌败血症中遇到庆大霉素治疗失败的情况,尽管根据VITEK 2检测该菌对庆大霉素敏感但对阿米卡星耐药,因此我们评估了其真正的敏感性和耐药机制。我们在一所大学医院的1年时间里筛选了2818株肺炎克雷伯菌分离株,并使用VITEK 2系统审查了抗菌药敏报告。通过肉汤微量稀释法(BMD)确定最低抑菌浓度,并研究16S rRNA甲基化酶基因和氨基糖苷类修饰酶的存在情况。根据VITEK 2系统,来自19例患者的总共131株耐阿米卡星分离株对庆大霉素不耐药。其中,我们能够从12例患者(63.2%)中收集分离株,并对每位患者的单个分离株进行检测。11株庆大霉素不耐药分离株(91.7%)通过BMD检测显示对阿米卡星和庆大霉素均具有高水平耐药性,且与armA基因有关。即使VITEK 2报告显示敏感,庆大霉素也不是治疗耐阿米卡星肺炎克雷伯菌的合适选择。