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人类bcr的cDNA序列,该基因在慢性髓细胞白血病中易位至abl癌基因。

cDNA sequence for human bcr, the gene that translocates to the abl oncogene in chronic myeloid leukaemia.

作者信息

Hariharan I K, Adams J M

出版信息

EMBO J. 1987 Jan;6(1):115-9. doi: 10.1002/j.1460-2075.1987.tb04727.x.

DOI:10.1002/j.1460-2075.1987.tb04727.x
PMID:3107980
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC553365/
Abstract

The hallmark of human chronic myeloid leukaemia is a 9;22 chromosome translocation that fuses most of the c-abl oncogene to the 5' portion of the breakpoint cluster region (bcr) gene, such that a hybrid bcr-abl mRNA and polypeptide are generated. To clarify further the nature of this translocation, we have analysed the structure of normal human bcr mRNA by isolating large cDNA clones that collectively span the entire coding region and extend 2.6 kb upstream of those previously described. The 3150-bp nucleotide sequence reported here includes 534 bp of a GC-rich 5' non-coding segment and indicates, in conjunction with published sequences, that the bcr polypeptide comprises 1271 amino acid residues. The predicted polypeptide is unrelated to serine or tyrosine kinases, or indeed to any previously published sequence; its structure provides no evidence of a transmembrane region. Since probes from throughout the 4.8-kb cloned region hybridized to both the 4.5 and 6.7 kb normal bcr transcripts, both RNAs contain most or all of that region.

摘要

人类慢性髓性白血病的标志是9号与22号染色体易位,该易位使大部分c-abl癌基因与断裂簇区域(bcr)基因的5'部分融合,从而产生一种杂种bcr-abl mRNA和多肽。为了进一步阐明这种易位的本质,我们通过分离大的cDNA克隆来分析正常人bcr mRNA的结构,这些克隆共同覆盖了整个编码区,并在先前描述的区域上游延伸了2.6 kb。此处报道的3150 bp核苷酸序列包括534 bp富含GC的5'非编码片段,并结合已发表的序列表明,bcr多肽由1271个氨基酸残基组成。预测的多肽与丝氨酸或酪氨酸激酶无关,实际上与任何先前发表的序列都无关;其结构没有提供跨膜区域的证据。由于来自整个4.8 kb克隆区域的探针与4.5 kb和6.7 kb正常bcr转录本都杂交,因此这两种RNA都包含该区域的大部分或全部。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8187/553365/c8153555e541/emboj00241-0120-a.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8187/553365/c8153555e541/emboj00241-0120-a.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8187/553365/c8153555e541/emboj00241-0120-a.jpg

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