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阐明钴卟啉促进水氧化 2e-/2H+与 4e-/4H+选择性的因素。

Elucidation of Factors That Govern the 2e/2H vs 4e/4H Selectivity of Water Oxidation by a Cobalt Corrole.

机构信息

School of Chemical Sciences, Indian Association for the Cultivation of Science, 2A & 2B Raja S. C. Mullick Road, Kolkata 700032, India.

Schulich Faculty of Chemistry, Technion-Israel Institute of Technology, Haifa 3200008, Israel.

出版信息

J Am Chem Soc. 2020 Dec 16;142(50):21040-21049. doi: 10.1021/jacs.0c08654. Epub 2020 Dec 1.

Abstract

Considering the importance of water splitting as the best solution for clean and renewable energy, the worldwide efforts for development of increasingly active molecular water oxidation catalysts must be accompanied by studies that focus on elucidating the mode of actions and catalytic pathways. One crucial challenge remains the elucidation of the factors that determine the selectivity of water oxidation by the desired 4e/4H pathway that leads to O rather than by 2e/2H to HO. We now show that water oxidation with the cobalt-corrole CoBr as electrocatalyst affords HO as the main product in homogeneous solutions, while heterogeneous water oxidation by the same catalyst leads exclusively to oxygen. Experimental and computation-based investigations of the species formed during the process uncover the formation of a Co(III)-superoxide intermediate and its preceding high-valent Co-oxyl complex. The competition between the base-catalyzed hydrolysis of Co(III)-hydroperoxide [Co(III)-OOH] to release HO and the electrochemical oxidation of the same to release O via [Co(III)-O] is identified as the key step determining the selectivity of water oxidation.

摘要

考虑到水分解作为清洁和可再生能源的最佳解决方案的重要性,全球范围内开发越来越活跃的分子水氧化催化剂的努力必须伴随着研究,重点阐明作用模式和催化途径。一个关键的挑战仍然是阐明决定水氧化选择性的因素,通过所需的 4e/4H 途径导致 O 而不是通过 2e/2H 到 HO。我们现在表明,用电化学催化剂钴卟啉 CoBr 进行水氧化可在均相溶液中得到 HO 作为主要产物,而相同催化剂的多相水氧化则仅导致氧气。在该过程中形成的物种的实验和基于计算的研究揭示了 Co(III)-超氧化物中间体及其先前的高价 Co-氧合配合物的形成。确定水氧化选择性的关键步骤是确定碱催化水解 Co(III)-过氧化物[Co(III)-OOH]以释放 HO 和电化学氧化相同的 Co(III)-O 通过 [Co(III)-O] 以释放 O 之间的竞争。

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