维持酿酒酵母杀伤性双链RNA质粒需要26个染色体基因。
Twenty-six chromosomal genes needed to maintain the killer double-stranded RNA plasmid of Saccharomyces cerevisiae.
作者信息
Wickner R B
出版信息
Genetics. 1978 Mar;88(3):419-25. doi: 10.1093/genetics/88.3.419.
Abstract
The double-stranded RNA killer plasmid gives yeast strains carrying it both the ability to secret a protein toxin and immunity to that toxin. This report describes a new series of mutants in chromsomal genes needed for killer plasmid maintenance (mak genes). These mutants comprise 12 complementation groups. There are a total of at least 26 mak genes. Each mak gene product is needed for plasmid maintenance in diploids as well as in haploids. None of these mak mutations prevent the killer plasmid from entering the mak- spores in the process of meiotic sporulation. Complementation between mak mutants can be performed by mating meitoic spores from a makx/+ plasmid-carrying diploid with a maky haploid. If x = y, about half the diploid clones formed lose the killer plasmid. If x not equal to y, complementation occurs, and all of the diploid clones are killers.
摘要
双链RNA杀伤质粒赋予携带它的酵母菌株分泌一种蛋白质毒素的能力以及对该毒素的免疫力。本报告描述了维持杀伤质粒所需的染色体基因（mak基因）中的一系列新突变体。这些突变体包含12个互补群。总共有至少26个mak基因。每个mak基因产物对于二倍体和单倍体中的质粒维持都是必需的。这些mak突变均不会阻止杀伤质粒在减数分裂孢子形成过程中进入mak-孢子。mak突变体之间的互补作用可以通过将来自携带makx/+质粒的二倍体的减数分裂孢子与maky单倍体进行交配来实现。如果x = y，大约一半形成的二倍体克隆会丢失杀伤质粒。如果x不等于y，则会发生互补作用，并且所有二倍体克隆都是杀伤性的。
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本文引用的文献
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