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高折射率,基于联二萘酚的手性纯硅氧烷。

High Refractive Index, Enantiopure Silicones Based on BINOL.

机构信息

Department of Chemistry and Chemical Biology, McMaster University, 1280 Main St., W., Hamilton, ON, L8S 4M1, Canada.

出版信息

Macromol Rapid Commun. 2022 May;43(9):e2200022. doi: 10.1002/marc.202200022. Epub 2022 Mar 8.

Abstract

The high refractive index aromatic compound, binaphthol (BINOL), is readily incorporated into silicone polymer chains using the Piers-Rubinsztajn (PR) reaction; alternating and random linear copolymers, and elastomers are available. The highest refractive index (RI) materials are BINOL rich. It is not possible to directly make high refractive index linear polymers with very short HSi-capped, telechelic silicone chains, as they do not react cleanly. However, chain extending short vinyl-capped BINOL macromers with simple arylsilanes using hydrosilylation leads to polymers with a molar mass of up to 8000 and refractive indices of up to 1.58. Elastomers are prepared using similar processes. The reactions are facile to practice and suggest BINOL can be harnessed in these and other processes to augment RI.

摘要

高折射率芳香族化合物联萘酚(BINOL)可通过 Piers-Rubinsztajn(PR)反应轻易地掺入硅氧烷聚合物链中,从而得到交替和随机线性共聚物和弹性体。折射率最高的材料是富含 BINOL 的材料。用 HSi 封端的短 telechelic 硅氧烷链直接制备高折射率线性聚合物是不可能的,因为它们不能进行清洁的反应。然而,通过硅氢加成反应将短的乙烯基封端的 BINOL 大分子单体与简单的芳基硅烷链扩展,可以得到摩尔质量高达 8000 且折射率高达 1.58 的聚合物。类似的过程也可用于制备弹性体。这些反应易于实施,并表明 BINOL 可以在这些和其他过程中得到利用,以提高折射率。

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