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顺式-2-羟基-2-苯基环己烷羧酸(环氯噻嗪酸)的立体化学

Stereochemistry of cis-2-hydroxy-2-phenyl-cyclohexanecarboxylic acid (cicloxilic acid).

作者信息

Turbanti L, Cebai G, Ceccarelli G

出版信息

Arzneimittelforschung. 1978;28(7a):1249-52.

PMID:582966
Abstract

The configuration of cis-2-hydroxy-2-phenyl-cyclohexanecarboxilic acid (cicloxilic acid) was deduced by comparing its NMR and IR spectra with those of its diastereoisomer and of their respective analogs, the 1-hydroxy(bicyclohexyl)-2-carboxylic acids. The diastereoisomer was prepared by converting cicloxilic acid to the corresponding 2-chloro-2-phenyl-cyclohexanecarboxylic acid and subsequent hydrolysis of the latter with aqueous solvents in the presence of wet silver oxide, or by simple solvolysis. The pair of 1-hydroxy(bicyclohexyl)-2-carboxylic acid was prepared from the respective phenylic terms by catalytic hydrogenation. Comparison of the NMR spectra revealed the spatial arrangement of the -H and -COOH groups on the carbon-alpha atom and the study of the interaction between the substitutents -OH and -COOH by IR spectrography revealed the position of the -OH group with respect to the -COOH group, as a result of which the configuration and conformation of the compounds under study were established. Cicloxilic acid is thus represented by the steric formula 4.

摘要

通过将顺式-2-羟基-2-苯基环己烷羧酸(环氯噻嗪酸)的核磁共振谱和红外光谱与其非对映异构体及其各自类似物1-羟基(双环己基)-2-羧酸的光谱进行比较,推断出了环氯噻嗪酸的构型。非对映异构体是通过将环氯噻嗪酸转化为相应的2-氯-2-苯基环己烷羧酸,然后在湿氧化银存在下用含水溶剂对后者进行水解,或者通过简单的溶剂解反应制备的。一对1-羟基(双环己基)-2-羧酸是由各自的苯基化合物通过催化氢化反应制备的。核磁共振谱的比较揭示了α-碳原子上-H和-COOH基团的空间排列,而通过红外光谱对取代基-OH和-COOH之间相互作用的研究揭示了-OH基团相对于-COOH基团的位置,据此确定了所研究化合物的构型和构象。因此,环氯噻嗪酸由空间结构式4表示。

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