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包含十个Alu家族成员的人类β-微管蛋白表达基因序列。

Sequence of an expressed human beta-tubulin gene containing ten Alu family members.

作者信息

Lee M G, Loomis C, Cowan N J

出版信息

Nucleic Acids Res. 1984 Jul 25;12(14):5823-36. doi: 10.1093/nar/12.14.5823.

Abstract

The complete sequence of a functionally expressed human beta-tubulin gene (5 beta) is presented. The amino acid sequence encoded by this gene constitutes a distinct isotype, differing from a previously described human beta-tubulin sequence at 21 positions throughout the polypeptide chain. The beta-tubulin coding sequence in 5 beta is interrupted by three intervening sequences of 1014, 117 and 4826 nucleotides. The largest of these contains ten members of the Alu family of middle repetitive sequences. Together, these regions account for sixty percent of this intervening sequence. Two of the Alu elements are juxtaposed head to tail, and share the same flanking direct repeat. The ten Alu sequences are substantially divergent, both from each other and from an Alu consensus sequence, and several contain deletions of up to half the entire sequence.

摘要

本文展示了一个功能表达的人类β-微管蛋白基因(5β)的完整序列。该基因编码的氨基酸序列构成一种独特的同型异构体,在整个多肽链的21个位置上与先前描述的人类β-微管蛋白序列不同。5β中的β-微管蛋白编码序列被三个分别为1014、117和4826个核苷酸的间隔序列中断。其中最大的间隔序列包含十个中等重复序列的Alu家族成员。这些区域共同占该间隔序列的60%。两个Alu元件头尾相连,并共享相同的侧翼直接重复序列。这十个Alu序列彼此之间以及与Alu共有序列都有很大差异,并且有几个包含多达整个序列一半的缺失。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/7e6e/320034/a65391976e24/nar00332-0286-a.jpg

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