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正常犬离体肾小管中乳酸和丙酮酸的代谢

Lactate and pyruvate metabolism in isolated renal tubules of normal dogs.

作者信息

Baverel G, Bonnard M, D'Armagnac de Castanet E, Pellet M

出版信息

Kidney Int. 1978 Dec;14(6):567-75. doi: 10.1038/ki.1978.165.

Abstract

The kinetics of lactate and pyruvate (1 and 5 mM in each case) metabolism was studied in isolated dog renal tubules. Utilization of these two substrates and the production of glucose, pyruvate, or lactate, and alanine were determined. The rates of lactate and pyruvate utilization and of glucose production were constant during 60 min of incubation. Glucose production from pyruvate was less than that from lactate. Addition of albumin to the incubation medium greatly inhibited lactate and pyruvate utilization at both substrate concentrations. It stimulated, however, glucose production from 1 mM, but not 5 mM, lactate or pyruvate. These effects were found to be due to the presence of fatty acids in the albumin solution used. In the absence of fatty acids, glucose production represented 35 to 40% of lactate uptake, but represented less than 20% of pyruvate uptake. Fatty acids markedly enhanced the percentage of transformation of lactate and pyruvate into glucose, and that of pyruvate into lactate. Alanine represented 20% or less of lactate and pyruvate uptake. These results suggest that fatty acids have a regulatory influence on lactate and pyruvate dog kidney metabolism.

摘要

在分离的犬肾小管中研究了乳酸和丙酮酸(每种情况下浓度均为1和5 mM)的代谢动力学。测定了这两种底物的利用情况以及葡萄糖、丙酮酸、乳酸和丙氨酸的生成情况。在孵育60分钟期间,乳酸和丙酮酸的利用速率以及葡萄糖的生成速率保持恒定。由丙酮酸生成葡萄糖的量少于由乳酸生成葡萄糖的量。向孵育培养基中添加白蛋白在两种底物浓度下均极大地抑制了乳酸和丙酮酸的利用。然而,它刺激了由1 mM而非5 mM乳酸或丙酮酸生成葡萄糖。发现这些作用是由于所用白蛋白溶液中存在脂肪酸。在不存在脂肪酸的情况下,葡萄糖生成量占乳酸摄取量的35%至40%,但占丙酮酸摄取量的不到20%。脂肪酸显著提高了乳酸和丙酮酸转化为葡萄糖以及丙酮酸转化为乳酸的百分比。丙氨酸占乳酸和丙酮酸摄取量的20%或更少。这些结果表明脂肪酸对犬肾中乳酸和丙酮酸的代谢具有调节作用。

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