mukB的两个突变等位基因，mukB是大肠杆菌染色体分配所必需的一个基因。

Two mutant alleles of mukB, a gene essential for chromosome partition in Escherichia coli.

作者信息

Yamanaka K, Mitani T, Feng J, Ogura T, Niki H, Hiraga S

机构信息

Department of Molecular Cell Biology, Kumamoto University School of Medicine, Japan.

出版信息

FEMS Microbiol Lett. 1994 Oct 15;123(1-2):27-31. doi: 10.1111/j.1574-6968.1994.tb07196.x.

DOI:10.1111/j.1574-6968.1994.tb07196.x

PMID:7988894

Abstract

The MukB protein is essential for chromosome partitioning in Escherichia coli and consists of 1484 amino acid residues (170 kDa). We have determined the base changes at the mutated sites of the mukB106 mutant and a newly isolated mutant, mukB33. These mutant mukB genes were each found to carry a single base-pair transition which leads to an amino acid substitution; a serine residue at position 33 was changed to phenylalanine in the case of mukB106, and an aspartic acid residue at position 1201 was changed to asparagine in the case of mukB33.

摘要

MukB蛋白对于大肠杆菌中的染色体分离至关重要，由1484个氨基酸残基组成（170 kDa）。我们已经确定了mukB106突变体和新分离的突变体mukB33突变位点处的碱基变化。发现这些突变的mukB基因各自携带一个导致氨基酸替换的单碱基对转换；在mukB106中，第33位的丝氨酸残基变为苯丙氨酸，而在mukB33中，第1201位的天冬氨酸残基变为天冬酰胺。