Lim V I
Institute of Protein Research, Russian Academy of Sciences, Pushchino, Moscow Region.
J Mol Biol. 1994 Jul 1;240(1):8-19. doi: 10.1006/jmbi.1994.1413.
Wobble rules for modified residues in the first anticodon position are derived. All known modifications are considered individually. Stereochemical analysis was made taking into account the interaction between the ribosomal A and P-site bound codon-anticodon duplexes. The wobble base-pair was considered as the right one if its formation did not lead to an uncompensated loss of hydrogen bonds or polar atom-ion bonds. From this requirement it follows that all modifications of U should restrict its translational specificity to purines (with the exception of xo5U, which should decode A, G and U). The restriction is carried out in a unified way: modifications inhibit the large propeller twist resulting from an increase of about 35 degrees in the torsion angle of the anticodon wobble base, interacting with the third codon base via a hydrogen-bonded water molecule. Such a twist is required to avoid a loss of the hydrogen bond of the bonded water molecule. The modifications in S2U, Se2U and Um should weaken their pairing with G, because they deform one of the two hydrogen bonds of the guanine NH2 group. G should be recognized by Se2U better than by S2U for the reason that the hydrogen bond Se...HN is weaker than the hydrogen bond S...HN. Among the modifications of C and G only that in k2C has a pronounced effect on wobble. The nucleoside k2C should pair only with A. The N-2 atom of k2C should be in the pyramidal state. The consequences following from the interduplex interaction are formulated. According to one of them, adenosine in the wobble position of the P-site tRNA should destabilize the A-site duplex. This can serve as an explanation for the fact that adenosine is very rarely observed in the anticodon wobble position.
推导了反密码子第一位修饰残基的摆动规则。对所有已知修饰进行了单独考虑。进行了立体化学分析,考虑了核糖体A位和P位结合的密码子 - 反密码子双链体之间的相互作用。如果摆动碱基对的形成不会导致氢键或极性原子 - 离子键的无补偿损失,则认为其是正确的。由此要求可知,U的所有修饰都应将其翻译特异性限制为嘌呤(xo5U除外,它应解码A、G和U)。这种限制以统一的方式进行:修饰抑制了反密码子摆动碱基扭转角增加约35度所导致的大的螺旋桨扭转,该反密码子摆动碱基通过氢键连接的水分子与第三位密码子碱基相互作用。这种扭转是为了避免结合的水分子氢键的损失。S2U、Se2U和Um中的修饰应削弱它们与G的配对,因为它们使鸟嘌呤NH2基团的两个氢键之一变形。Se2U识别G应比S2U更好,原因是Se...HN氢键比S...HN氢键弱。在C和G的修饰中,只有k2C中的修饰对摆动有明显影响。核苷k2C应仅与A配对。k2C的N - 2原子应处于锥形状态。阐述了双链体间相互作用产生的后果。根据其中之一,P位tRNA摆动位置的腺苷应使A位双链体不稳定。这可以解释为什么在反密码子摆动位置很少观察到腺苷。