Ysern X, Fields B A, Bhat T N, Goldbaum F A, Dall'Acqua W, Schwarz F P, Poljak R J, Mariuzza R A
Center for Drug Evaluation and Research, F.D.A., Rockville, MD 20857.
J Mol Biol. 1994 May 13;238(4):496-500. doi: 10.1006/jmbi.1994.1309.
The three-dimensional structure of a site-directed mutant of the bacterially expressed Fv fragment from monoclonal antibody D1.3, complexed to the specific antigen lysozyme has been determined to a nominal resolution of 1.8 A using X-ray diffraction data. The replacement of VL Trp92 by Asp allows two water molecules to occupy space taken by Trp92 in the wild-type complex, in agreement with a previous observation that water molecules play an important role in stabilizing this antigen-antibody complex. The equilibrium constant for the binding of the mutant Fv to the antigen decreases by three orders of magnitude (from 2.3 x 10(8) M-1 to 2.6 x 10(5) M-1). Titration calorimetry shows that this results from a smaller negative binding enthalpy (delta delta H = -16 kJ mol-1 at 24 degrees C), whereas the value of the binding entropy is not affected. Since in the complex between the mutated Fv and antigen the buried area has decreased relative to that of the wild-type Fv by about 150 A2, the contribution of the buried unit area to the decrease in free energy (delta Gzero) is approximately 117 J mol-1 (28 cal mol-1) per A2. The loss of interatomic contacts in replacing Trp by Asp permits an approximate calculation for the contribution of van der Waals interactions made by Trp92 in this complex, which gives an average of 2.1 kJ mol-1 (0.5 kcal mol-1) for contacts between carbon atoms.
利用X射线衍射数据,已确定细菌表达的单克隆抗体D1.3的Fv片段定点突变体与特异性抗原溶菌酶复合物的三维结构,标称分辨率为1.8埃。用天冬氨酸取代VL Trp92,使两个水分子占据野生型复合物中Trp92所占空间,这与先前观察到的水分子在稳定该抗原 - 抗体复合物中起重要作用一致。突变体Fv与抗原结合的平衡常数下降了三个数量级(从2.3×10⁸ M⁻¹降至2.6×10⁵ M⁻¹)。滴定热分析法表明,这是由于结合焓变小(24℃时ΔΔH = -16 kJ mol⁻¹),而结合熵的值不受影响。由于在突变的Fv与抗原的复合物中,埋藏面积相对于野生型Fv减少了约150 Ų,埋藏单位面积对自由能降低(ΔG⁰)的贡献约为每Ų 117 J mol⁻¹(28 cal mol⁻¹)。用天冬氨酸取代色氨酸导致原子间接触的丧失,从而可以近似计算Trp92在此复合物中范德华相互作用的贡献,碳原子间接触的平均贡献为2.1 kJ mol⁻¹(0.5 kcal mol⁻¹)。