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N-亚硝基六亚甲基亚胺代谢生成与大鼠肝脏核酸结合的1,6-己二醇。

Metabolism of N-nitrosohexamethyleneimine to give 1,6-hexanediol bound to rat liver nucleic acids.

作者信息

Ross A E, Mirvish S S

出版信息

J Natl Cancer Inst. 1977 Mar;58(3):651-5. doi: 10.1093/jnci/58.3.651.

Abstract

Rats were gavaged with the liver carcinogen H-nitrosohexamethyleneimine labeled with 3H or 14C and killed 16 hours later. The liver RNA and DNA were isolated and hydrolyzed with 1 M HCl at 100 degrees C. Chromatography of the 3H-labelled RNA hydrolysate on a cation exchange resin (NH4+ form), with water elution, separated five radioactive peaks, with peak "E" containing 27% of the bound 3H. There were no radioactive peaks in the 7-substituted guanine region. Hydrolysis of the 3H-labeled DNA gave a similar profile, but E contained only 5% of the 3H. The major component of E was identified as 1,6-hexanediol by its behavior and/or that of its benzoate derivative on cation exchange, anion exchange, thin-layer and gas-liquid chromatography, and by recrystallization of a mixture of the E and diol benzoates to constant specific radioactivity.

摘要

给大鼠灌胃用³H或¹⁴C标记的肝致癌物N-亚硝基六亚甲基亚胺,16小时后处死。分离肝脏RNA和DNA,并在100℃下用1M盐酸水解。³H标记的RNA水解产物在阳离子交换树脂(NH₄⁺形式)上进行色谱分析,用水洗脱,分离出五个放射性峰,峰“E”含有结合³H的27%。在7-取代鸟嘌呤区域没有放射性峰。³H标记的DNA水解得到类似的图谱,但E仅含有³H的5%。通过E及其苯甲酸酯衍生物在阳离子交换、阴离子交换、薄层和气相色谱上的行为,以及通过将E和二醇苯甲酸酯的混合物重结晶至恒定比放射性,将E的主要成分鉴定为1,6-己二醇。

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