Hage J P, Llobet A, Sawyer D T
Department of Chemistry, Texas A&M University, College Station 77843-3255, USA.
Bioorg Med Chem. 1995 Oct;3(10):1383-8. doi: 10.1016/0968-0896(95)00123-x.
Several iron complexes [FeII(bpy)2(2+), FeII(OPPh3)4(2+), and FeII(PA)2] in combination with hydrogen peroxide (HOOH) catalytically hydroxylate aromatic substrates (ArH). The base-induced nucleophilic addition of HOOH to the electrophilic iron center yields the reactive intermediate of Fenton reagents [FeIILx2+ + HOOH<-->Lx+FeIIOOH(BH+)(1)]. The latter includes a 'stabilized' hydroxyl radical that is able to replace an aromatic hydrogen (H) with a hydroxyl group (HO) via an initial addition reaction. With PhCH3 and PhCH2CH3 as substrates free HO. (from the radiolysis of H2O) reacts via aryl addition (97 and 85%, respectively) to give Ar-Ar as the predominant product, whereas 1 favors H-atom abstraction from the alkyl group (50 and 80%, respectively) and the only detectable products from aryl addition are the respective substituted phenols (o:p-ArOH). Other substituted benzenes (PhX) undergo addition by free HO at the ortho and para aryl carbons (o:p ratio, 2), followed by dimerization and elimination of two H2O molecules to yield substituted biphenyls. In contrast, 1 reacts with PhX to yield substituted phenol (ArOH; o:p ratio, 0.5-1.1). With phenol (PhOH) as the substrate, reaction with 1 yields mainly catechol (o-Ar(OH)2; o:p ratio, 20). In a solvent matrix of MeCN:H2O (3:1 mol:mol ratio) the reaction efficiencies with FeII(bpy)2(2+) and FeII(OPPh3)4(2+) for the hydroxylation of benzene to phenol are 36 and 42%, respectively (product per HOOH).
几种铁配合物[FeII(bpy)2(2+)、FeII(OPPh3)4(2+)和FeII(PA)2]与过氧化氢(HOOH)结合,可催化芳香族底物(ArH)的羟基化反应。碱诱导HOOH向亲电铁中心的亲核加成产生了芬顿试剂的反应中间体[FeIILx2+ + HOOH<-->Lx+FeIIOOH(BH+)(1)]。后者包含一个“稳定的”羟基自由基,该自由基能够通过初始加成反应将芳香氢(H)替换为羟基(HO)。以PhCH3和PhCH2CH3为底物时,游离的HO·(来自H2O的辐射分解)分别通过芳基加成反应(分别为97%和85%)反应,以Ar-Ar作为主要产物,而1更倾向于从烷基中夺取氢原子(分别为50%和80%),芳基加成反应中唯一可检测到的产物是相应的取代酚(o:p-ArOH)。其他取代苯(PhX)在邻位和对位芳基碳上通过游离的HO·进行加成反应(o:p比例为2),随后二聚并消除两个H2O分子,生成取代联苯。相比之下,1与PhX反应生成取代酚(ArOH;o:p比例为0.5 - 1.1)。以苯酚(PhOH)为底物时,与1反应主要生成邻苯二酚(o-Ar(OH)2;o:p比例为20)。在MeCN:H2O(3:1摩尔:摩尔比例)的溶剂基质中,FeII(bpy)2(2+)和FeII(OPPh3)4(2+)将苯羟基化为苯酚的反应效率分别为36%和42%(每HOOH的产物)。