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Tau蛋白在复制叉处的前导链聚合酶复合物中保护β亚基。

Tau protects beta in the leading-strand polymerase complex at the replication fork.

作者信息

Kim S, Dallmann H G, McHenry C S, Marians K J

机构信息

Graduate Program in Molecular Biology, Cornell University Graduate School of Medical Sciences, New York, New York 10021, USA.

出版信息

J Biol Chem. 1996 Feb 23;271(8):4315-8. doi: 10.1074/jbc.271.8.4315.

Abstract

Replication forks formed in the absence of the tau subunit of the DNA polymerase III holoenzyme produce shorter leading and lagging strands than when tau is present. We show that one reason for this is that in the absence of tau, but in the presence of the gamma-complex, leading-strand synthesis is no longer highly processive. In the absence of tau, the size of the leading strand becomes proportional to the concentration of beta and inversely proportional to the concentration of the gamma-complex. In addition, the beta in the leading-strand complex is no longer resistant to challenge by either anti-beta antibodies or poly(dA):oligo(dT). Thus, tau is required to cement a processive leading-strand complex, presumably by preventing removal of beta catalyzed by the gamma-complex.

摘要

在缺乏DNA聚合酶III全酶的tau亚基的情况下形成的复制叉,与存在tau时相比,产生的前导链和后随链更短。我们表明,造成这种情况的一个原因是,在缺乏tau但存在γ复合物的情况下,前导链合成不再具有高度持续性。在缺乏tau时,前导链的大小与β的浓度成正比,与γ复合物的浓度成反比。此外,前导链复合物中的β不再抵抗抗β抗体或聚(dA):寡聚(dT)的挑战。因此,tau是巩固持续性前导链复合物所必需的,大概是通过防止γ复合物催化的β的去除来实现的。

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