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铜对人血红蛋白的氧化作用。β-93位残基硫醇基团的作用机制及推测作用

Oxidation of human haemoglobin by copper. Mechanism and suggested role of the thiol group of residue beta-93.

作者信息

Winterbourn C C, Carrell R W

出版信息

Biochem J. 1977 Jul 1;165(1):141-8. doi: 10.1042/bj1650141.

Abstract

Addition of Cu(II) ions to human oxyhaemoglobin caused the rapid oxidation of the haem groups of the beta-chain. Oxidation required binding of Cu(II) to sites involving the thiol group of beta-93 residues and was prevented when these groups were blocked with iodoacetamide or N-ethylmaleimide. Equilibrium-dialysis studies showed three pairs of binding sites, two pairs with high affinity for Cu(II) and one pair with lower affinity. It was the second pair of high-affinity sites that were blocked with iodoacetamide and were involved in haem oxidation. Cu(II) oxidized deoxyhaemoglobin at least ten times as fast as oxyhaemoglobin, and analysis of rates suggested that binding rather than electron transfer was the rate-determining step. No thiol-group oxidation to disulphides occurred during the period of haem oxidation, although it did occur subsequently in the presence of oxygen, or when Cu(II) was added to methaemoglobin. It is proposed that thiol oxidation did not occur because there exists a pathway of electron transfer between the haem group and copper bound to the beta-93 thiol groups. The route for this electron transfer is discussed, as well as the implications as to the function of the beta-93 cysteine in the haemoglobin molecule.

摘要

向人氧合血红蛋白中添加铜(II)离子会导致β链血红素基团迅速氧化。氧化需要铜(II)与涉及β-93残基硫醇基团的位点结合,当这些基团被碘乙酰胺或N-乙基马来酰亚胺阻断时,氧化反应就会被阻止。平衡透析研究显示有三对结合位点,两对对铜(II)具有高亲和力,一对具有较低亲和力。正是第二对高亲和力位点被碘乙酰胺阻断,并参与了血红素氧化。铜(II)氧化脱氧血红蛋白的速度至少是氧化氧合血红蛋白的十倍,对反应速率的分析表明,结合而非电子转移是限速步骤。在血红素氧化期间,没有发生硫醇基团氧化成二硫化物的情况,尽管在随后有氧存在时,或者当铜(II)添加到高铁血红蛋白中时确实会发生这种情况。有人提出没有发生硫醇氧化是因为在血红素基团和与β-93硫醇基团结合的铜之间存在一条电子转移途径。本文讨论了这种电子转移的途径,以及β-93半胱氨酸在血红蛋白分子中的功能意义。

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