Suppr超能文献

包埋的单倍体和二倍体酵母形成假菌丝。

Development of pseudohyphae by embedded haploid and diploid yeast.

作者信息

Lo W S, Raitses E I, Dranginis A M

机构信息

Department of Biological Sciences, St. John's University, Jamaica, New York 11439, USA.

出版信息

Curr Genet. 1997 Sep;32(3):197-202. doi: 10.1007/s002940050266.

Abstract

Diploid strains of S. cerevisiae are known to develop pseudohyphae in response to starvation for nitrogen. We report that both haploid and diploid yeast grow in a filamentous form when embedded in solid media. This is not a response to starvation, since yeast grown on rich media and overlaid with rich agar grow within the agar as pseudohyphae. While we find that the only element of diploidy required for formation of pseudohyphae in response to nitrogen starvation is the a1/alpha 2 repressor, pseudohyphal development by embedded cells does not require a1/alpha 2. Deletion of BUD 5 prevented the formation of pseudohyphae by embedded cells, suggesting that these structures are the result of ordered filament formation rather than agar penetration. Deletion of STE 12 prevented the formation of pseudohyphae by all cell types, showing that the same signal transduction pathway is used by embedded cells as by those responding to nitrogen starvation. Different cell types of yeast thus form filaments in response to several kinds of environmental stimuli.

摘要

已知酿酒酵母的二倍体菌株在氮饥饿时会形成假菌丝。我们报告,单倍体和二倍体酵母嵌入固体培养基时都会以丝状形式生长。这并非对饥饿的反应,因为在丰富培养基上生长并覆盖有丰富琼脂的酵母会在琼脂内以假菌丝形式生长。虽然我们发现响应氮饥饿形成假菌丝所需的二倍体的唯一要素是a1/α2阻遏物,但嵌入细胞的假菌丝发育并不需要a1/α2。删除BUD 5可防止嵌入细胞形成假菌丝,这表明这些结构是有序丝状体形成的结果,而非琼脂穿透的结果。删除STE 12可防止所有细胞类型形成假菌丝,这表明嵌入细胞与响应氮饥饿的细胞使用相同的信号转导途径。因此,酵母的不同细胞类型会响应几种环境刺激形成丝状体。

文献检索

告别复杂PubMed语法,用中文像聊天一样搜索,搜遍4000万医学文献。AI智能推荐,让科研检索更轻松。

立即免费搜索

文件翻译

保留排版,准确专业,支持PDF/Word/PPT等文件格式,支持 12+语言互译。

免费翻译文档

深度研究

AI帮你快速写综述,25分钟生成高质量综述,智能提取关键信息,辅助科研写作。

立即免费体验