枯草芽孢杆菌的galE基因在葡萄糖和半乳糖存在的情况下是必需的。
The Bacillus subtilis galE gene is essential in the presence of glucose and galactose.
作者信息
Krispin O, Allmansberger R
机构信息
Lehrstuhl für Mikrobiologie, Universität Erlangen-Nürnberg, Erlangen, Germany.
出版信息
J Bacteriol. 1998 Apr;180(8):2265-70. doi: 10.1128/JB.180.8.2265-2270.1998.
Abstract
Bacillus subtilis is unable to grow by consuming galactose because it is unable to transport it into the cell. The transcription of galE is not influenced by galactose but is repressed by glucose. Galactose is toxic for galE-negative bacteria because it results in elevated levels of metabolic intermediates. These negative effects are reduced in galK and galT mutants. Glucose is also toxic for galE-negative strains.
摘要
枯草芽孢杆菌无法通过消耗半乳糖来生长，因为它无法将半乳糖转运到细胞内。galE的转录不受半乳糖影响，但会受到葡萄糖的抑制。半乳糖对galE阴性细菌有毒，因为它会导致代谢中间产物水平升高。在galK和galT突变体中，这些负面影响会降低。葡萄糖对galE阴性菌株也有毒性。
Zotero 插件