Departments of Pediatric and Adolescent Medicine, Mayo Clinic College of Medicine, Rochester, MN, USA.
Cell Cycle. 2010 May;9(9):1711-6. doi: 10.4161/cc.9.9.11314. Epub 2010 May 27.
A longstanding hypothesis in the field of cancer biology is that aneuploidy causes cancer by promoting loss of chromosomes that contain tumor suppressor genes. By crossing aneuploidyprone Bub1 hypomorphic mice onto a heterozygous null background for p53, we provided conclusive evidence for this idea.(1) Surprisingly, the tumors that developed in this model had not just lost the chromosome 11 copy harboring wild-type p53, but had also gained an extra copy of chromosome 11 bearing the p53 null allele. Here we report that a similar chromosome-reshuffling blueprint drives colonic tumorigenesis in Bub1 hypomorphic mice that are heterozygous for Apc(Min), but now involving chromosome 18. These extended studies highlight that in order for whole chromosome instability to drive tumorigenesis, it needs to establish tumor suppressor gene loss of heterozygosity while retaining two copies of the other genes on the chromosome. Additional restrictions seem to apply to whole chromosome instability as a cancer causing mechanism, which will be discussed in this paper.
在癌症生物学领域,一个长期存在的假说认为,非整倍体通过促进包含肿瘤抑制基因的染色体丢失而导致癌症。通过将易患非整倍体的 Bub1 功能减弱的小鼠与 p53 杂合缺失的背景杂交,我们为这一观点提供了确凿的证据。(1)令人惊讶的是,在该模型中发展的肿瘤不仅失去了携带野生型 p53 的 11 号染色体拷贝,而且还获得了额外的 11 号染色体拷贝,携带 p53 缺失等位基因。在这里,我们报告说,类似的染色体重排蓝图驱动 Bub1 功能减弱的 Apc(Min)杂合小鼠的结肠肿瘤发生,但现在涉及 18 号染色体。这些扩展研究强调,为了使全染色体不稳定性驱动肿瘤发生,它需要在保留染色体上其他基因的两个拷贝的同时,建立肿瘤抑制基因的杂合性丢失。本文将讨论全染色体不稳定性作为致癌机制的其他限制。