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顺式二氯[4,4,5,5-四甲基-2-(2-吡啶基)-2-咪唑啉-1-氧代]-钯(II) 四氢呋喃半溶剂化物

cis-Dichlorido[4,4,5,5-tetra-methyl-2-(2-pyrid-yl)-2-imidazoline-1-ox-yl]-palladium(II) tetra-hydro-furan hemi-solvate.

作者信息

Badeche Sihem, Rouag Djamil Azzedine, Benmebarek Sabrina, Bouaoud Salah-Eddine, Golhen Stéphane

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2008 Feb 20;64(Pt 3):m487-8. doi: 10.1107/S1600536808004406.

Abstract

The asymmetric unit of the title complex, [PdCl(2)(C(12)H(16)N(3)O)]·0.5C(4)H(8)O, consists of one palladium complex in a general position and one half tetra-hydro-furan (THF) solvent mol-ecule, with the O atom lying on a twofold rotation axis. The Pd(II) atom is bound to one chelating imino nitroxide radical through two N atoms, one from the pyridyl ring and the other from the imidazoline ring. The coordination of the metal centre is completed by two Cl atoms in a cis configuration, leading to a quasi-square-planar coordination of the metal centre. The four atoms that define the Pd(II) coordination environment and the eight atoms that belong to the pyridylimine fragment are coplanar, with no deviation larger than 0.087 (5) Å. In the crystal structure, inter-molecular inter-actions shorter than the corresponding van der Waals radii sum are observed only between Pd(II) complexes, and no short contact is observed around the THF mol-ecule. Weak C-H⋯O and C-H⋯Cl inter-actions yield a two-dimensional network of complexes in the (101) plane.

摘要

标题配合物[PdCl₂(C₁₂H₁₆N₃O)]·0.5C₄H₈O的不对称单元由一个处于一般位置的钯配合物和半个四氢呋喃(THF)溶剂分子组成,O原子位于二重旋转轴上。Pd(II)原子通过两个N原子与一个螯合亚氨基氮氧自由基相连,一个N原子来自吡啶环,另一个来自咪唑啉环。金属中心的配位由两个呈顺式构型的Cl原子完成,导致金属中心形成准平面正方形配位。定义Pd(II)配位环境的四个原子和属于吡啶基亚胺片段的八个原子共面,偏差不大于0.087 (5) Å。在晶体结构中,仅在Pd(II)配合物之间观察到短于相应范德华半径之和的分子间相互作用,在THF分子周围未观察到短接触。弱的C—H⋯O和C—H⋯Cl相互作用在(101)平面上形成二维配合物网络。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/1229/2960750/ef3a27f8977e/e-64-0m487-fig1.jpg

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