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维斯纳病毒基因组中不存在环形排列且大量冗余的序列。

Absence of circularly permuted and largely redundant sequences in the genome of visna virus.

作者信息

Vigne R, Filippi P, Brahic M, Tamalet J

出版信息

J Virol. 1978 Nov;28(2):543-50. doi: 10.1128/JVI.28.2.543-550.1978.

Abstract

A previous study of the infectivity of visna virus proviral DNA suggested that the genetic information of the virus is distributed over at least two of the RNA subunits. Because the genetic complexity of visna virus corresponds to the size of one subunit, this result may imply that sequence redundancies exist within each subunit. In the present article we have examined this question by constructing a map of the large RNase T1-resistant oligonucleotides of the viral genome. Our principal results are as follows: (i) all 36S RNA subunits have the same genetic content regardless of their polyadenylic acid [poly(A)] content; (ii) the poly(A) tract is present at the 3' end of the molecule; and (iii) the recoveries of 19 large RNase T1-resistant oligonucleotides from poly(A)-tagged RNA fragments of various sizes demonstrate that the oligonucleotides are organized in the same linear order within all subunits. Our results, therefore, exclude the existence of large sequence redundancies in the genome of visna virus.

摘要

先前一项关于维斯纳病毒前病毒DNA感染性的研究表明,该病毒的遗传信息分布在至少两个RNA亚基上。由于维斯纳病毒的遗传复杂性与一个亚基的大小相对应,这一结果可能意味着每个亚基内存在序列冗余。在本文中,我们通过构建病毒基因组中对核糖核酸酶T1有抗性的大寡核苷酸图谱来研究这个问题。我们的主要结果如下:(i)所有36S RNA亚基都具有相同的遗传内容,无论其聚腺苷酸[poly(A)]含量如何;(ii)聚(A)尾位于分子的3'端;(iii)从各种大小的聚(A)标记的RNA片段中回收的19种对核糖核酸酶T1有抗性的大寡核苷酸表明,这些寡核苷酸在所有亚基中以相同的线性顺序排列。因此,我们的结果排除了维斯纳病毒基因组中存在大量序列冗余的可能性。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/3b33/354302/ecd452a4d149/jvirol00203-0131-a.jpg

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