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二氯双{[N-(二甲基氨基)二甲基甲硅烷基]-2,6-二甲基苯胺基-κN,N'}锆(IV)

Dichloridobis{N-[(dimethyl-amino)dimethyl-silyl]-2,6-dimethyl-anilido-κN,N'}zirconium(IV).

作者信息

Chen Juan

机构信息

Department of Chemistry, Taiyuan Teachers College, Taiyuan 030031, People's Republic of China.

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2009 Oct 7;65(Pt 11):m1307. doi: 10.1107/S1600536809039804.

Abstract

The monomeric title zirconium(IV) compound, [Zr(C(12)H(21)N(2)Si)(2)Cl(2)], was prepared by the metathetical reaction of LiN(SiMe(2)NMe(2))(2,6-Me(2)C(6)H(3)) with zirconium tetra-chloride. The Zr(IV) atom is N,N'-chelated by the N-silylated anilido ligand. Along with two Cl atoms, the six-coordinated Zr(IV) atom demonstrates a highly distorted octa-hedral geometry. The two ligands around the Zr(IV) atom are arranged cis to each other and obey the C(2) symmetry operation. That means the asymmetric unit consists of only half of the mol-ecular compound and the complete mol-ecule is generated by a twofold axis. The two ends of the N-Si-N chelating unit exhibit different affinities for the metal center. The Zr-N(amino) bond is longer than the Zr-N(anilido) bond.

摘要

通过[LiN(SiMe₂NMe₂)(2,6-Me₂C₆H₃)]₂与四氯化锆的复分解反应制备了单体标题锆(IV)化合物[Zr(C₁₂H₂₁N₂Si)₂Cl₂]。Zr(IV)原子被N-硅烷基化的苯胺基配体进行N,N'-螯合。除两个Cl原子外,六配位的Zr(IV)原子呈现出高度扭曲的八面体几何构型。Zr(IV)原子周围的两个配体彼此顺式排列并服从C₂对称操作。这意味着不对称单元仅由分子化合物的一半组成,完整分子由二重轴生成。N-Si-N螯合单元的两端对金属中心表现出不同的亲和力。Zr-N(氨基)键长于Zr-N(苯胺基)键。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/f984/2970990/f551f0a09edd/e-65-m1307-fig1.jpg

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