双（1,10-菲咯啉-κN,N'）（硫酸根-κO,O'）镉（II）-1,3-丙二醇溶剂合物
Bis(1,10-phenanthroline-κN,N')(sulfato-κO,O')cadmium(II) propane-1,3-diol solvate.
作者信息
Zhong Kai-Long, Cui Jiang-Dong
机构信息
Department of Applied Chemistry, Nanjing College of Chemical Technology, Nanjing 210048, People's Republic of China.
出版信息
Acta Crystallogr Sect E Struct Rep Online. 2010 Jun 18;66(Pt 7):m817-8. doi: 10.1107/S1600536810022518.
In the title compound, [Cd(SO(4))(C(12)H(8)N(2))(2)]·C(3)H(8)O(2), the Cd(II) atom has a distorted octa-hedral coordination composed of four N atoms from two chelating 1,10-phenanthroline ligands and two O atoms from an O,O'-bidentate sulfate group. The two chelating NCCN groups subtend a dihedral angle of 82.21 (9)°. The Cd(II) ion, the S atom and the middle C atom of the propane-1,3-diol solvent mol-ecule are located on special positions, site symmetry 2. The solvate features a pair of O-H⋯O hydrogen bonds with the uncoordinated O atoms of the sulfate ion. The OH group of the propane-1,3-diol solvent is disordered over two positions of equal occupancy.
在标题化合物[Cd(SO₄)(C₁₂H₈N₂)₂]·C₃H₈O₂中，Cd(II)原子具有扭曲的八面体配位，由来自两个螯合的1,10-菲咯啉配体的四个N原子和来自一个O,O'-双齿硫酸根的两个O原子组成。两个螯合的NCCN基团形成的二面角为82.21 (9)°。Cd(II)离子、S原子和丙二醇溶剂分子的中间C原子位于特殊位置，位点对称性为2。该溶剂化物具有一对与硫酸根离子未配位的O原子形成的O-H⋯O氢键。丙二醇溶剂的OH基团在两个占有率相等的位置上无序分布。
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