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黄嘌呤氧化酶的作用机制。快速和极快速钼电子顺磁共振信号之间的关系。

The mechanism of action of xanthine oxidase. The relationship between the rapid and very rapid molybdenum electron-paramagnetic-resonance signals.

作者信息

Bray R C, Gutteridge S, Stotter D A, Tanner S J

出版信息

Biochem J. 1979 Jan 1;177(1):357-60. doi: 10.1042/bj1770357.

Abstract

On the basis of the work of Gutteridge, Tanner & Bray [Biochem. J. (1978) 175, 887-897] and of other data in the literature, a mechanism for the reaction of xanthine oxidase with reducing substrates is proposed. In the Michaelis complex, xanthine is bound to molybdenum via the N-9 nitrogen atom. Coupled transfer of two electrons to molybdenum and the C-8 proton to the enzyme yields (Enzyme)-Mo-SH. Concerted with this process, reaction of the xanthine residue with a nucleophile in the active centre yields a covalent intermediate that breaks down to give the product by alternative pathways at high and at low pH values.

摘要

基于古特里奇、坦纳和布雷的研究工作[《生物化学杂志》(1978年)175卷,887 - 897页]以及文献中的其他数据,提出了黄嘌呤氧化酶与还原性底物反应的机制。在米氏复合物中,黄嘌呤通过N - 9氮原子与钼结合。两个电子向钼的耦合转移以及C - 8质子向酶的转移产生(酶)- Mo - SH。与此过程协同进行的是,黄嘌呤残基与活性中心的亲核试剂反应生成共价中间体,该中间体在高pH值和低pH值下通过不同途径分解生成产物。

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