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轴突的粗细为什么会不同?

Why do axons differ in caliber?

机构信息

Department of Neuroscience, University of Pennsylvania, Philadelphia, Pennsylvania 19104-6396, USA.

出版信息

J Neurosci. 2012 Jan 11;32(2):626-38. doi: 10.1523/JNEUROSCI.4254-11.2012.

DOI:10.1523/JNEUROSCI.4254-11.2012
PMID:22238098
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC3571697/
Abstract

CNS axons differ in diameter (d) by nearly 100-fold (∼0.1-10 μm); therefore, they differ in cross-sectional area (d(2)) and volume by nearly 10,000-fold. If, as found for optic nerve, mitochondrial volume fraction is constant with axon diameter, energy capacity would rise with axon volume, also as d(2). We asked, given constraints on space and energy, what functional requirements set an axon's diameter? Surveying 16 fiber groups spanning nearly the full range of diameters in five species (guinea pig, rat, monkey, locust, octopus), we found the following: (1) thin axons are most numerous; (2) mean firing frequencies, estimated for nine of the identified axon classes, are low for thin fibers and high for thick ones, ranging from ∼1 to >100 Hz; (3) a tract's distribution of fiber diameters, whether narrow or broad, and whether symmetric or skewed, reflects heterogeneity of information rates conveyed by its individual fibers; and (4) mitochondrial volume/axon length rises ≥d(2). To explain the pressure toward thin diameters, we note an established law of diminishing returns: an axon, to double its information rate, must more than double its firing rate. Since diameter is apparently linear with firing rate, doubling information rate would more than quadruple an axon's volume and energy use. Thicker axons may be needed to encode features that cannot be efficiently decoded if their information is spread over several low-rate channels. Thus, information rate may be the main variable that sets axon caliber, with axons constrained to deliver information at the lowest acceptable rate.

摘要

中枢神经系统轴突的直径(d)差异近 100 倍(∼0.1-10 μm);因此,它们的横截面积(d(2))和体积差异近 10000 倍。如果像视神经那样,线粒体体积分数与轴突直径保持恒定,那么能量容量将随着轴突体积的增加而增加,也随着 d(2)的增加而增加。我们想知道,在空间和能量的限制下,是什么功能要求决定了轴突的直径?我们调查了五种物种(豚鼠、大鼠、猴子、蝗虫、章鱼)中几乎涵盖所有直径范围的 16 个纤维群,发现以下几点:(1)细轴突数量最多;(2)对于九个已识别的轴突类别的估计,较细纤维的平均发射频率较低,而较厚纤维的频率较高,范围从 ∼1 到 >100 Hz;(3)一个束的纤维直径分布,无论是狭窄还是广泛,无论是对称还是偏斜,都反映了其单个纤维传递的信息率的异质性;(4)线粒体体积/轴突长度呈上升趋势,至少呈 d(2)上升。为了解释向细直径的压力,我们注意到一个已确立的收益递减规律:为了使信息率翻倍,轴突必须将其发射率提高一倍以上。由于直径显然与发射率呈线性关系,因此将信息率提高一倍将使轴突的体积和能量使用增加四倍以上。如果将信息分布在几个低速率通道中,则无法有效地解码某些特征,因此可能需要更粗的轴突来编码这些特征。因此,信息率可能是决定轴突口径的主要变量,轴突受到限制,以最低可接受的速率传递信息。